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# Is 2|xy^2|> 0?

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05 May 2013, 10:35
5
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Question Stats:

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Is 2|xy^2|> 0?

(1) x > 0

(2) xy > 0
[Reveal] Spoiler: OA

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05 May 2013, 11:45
Hi
I think the question is flawed....U need to check it again...I may be wrong, If i am than pls correct me!

Consider kudos if my post helps!!!!!

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05 May 2013, 11:50
3
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B..
so as to confirm that it equation is not equal to zero..
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Last edited by anish123ster on 05 May 2013, 14:02, edited 1 time in total.

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05 May 2013, 13:28
1
KUDOS
B
2nd option is necessary
Just need to see if the expression is not 0.
1 alone cant assure that, but 2 alone can

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05 May 2013, 15:35
1
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The given condition will be true if both x and y are not zero. B clearly states that. Hence B.

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05 May 2013, 20:35
3
KUDOS
Zarrolou wrote:
Is $$2|xy^2|> 0$$?

A)$$x>0$$

B)$$xy>0$$

This is a DS I created, I'll post the OA and the OE after some discussion

If you want give it a try, Kudos to the first user(s) who got it right!

This Q . asks Is $$2|xy^2|> 0$$? or $$|xy^2|> 0$$?

Statement :: 1 --- > $$x>0$$ .. Dont't Know the value of Y ,.... It can be integer or 0 as well. Therefore, Insufficient.

Statement :: 2--- > $$xy>0$$ ........ This means that either of them has +ve signs or -ve signs. Because for both the cases the condition ...$$xy>0$$ must be true. & if we use these values in the Q, stem... The result must be same for both the signs. Therefore, Sufficient.

Hence ................ B .
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05 May 2013, 21:13
1
KUDOS
missed the point that y could be equal to 0....Of course anopther vote for B

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05 May 2013, 22:05
1
KUDOS
Zarrolou wrote:
Is $$2|xy^2|> 0$$?

A)$$x>0$$

B)$$xy>0$$

This is a DS I created, I'll post the OA and the OE after some discussion

If you want give it a try, Kudos to the first user(s) who got it right!

The question is asking , IS a mod quantity >0? This will always be true, unless there is a possibility that this mod quantity CAN be zero.

From F.S 1, we know that only x>0. y can be 0, in which case we get a NO and y can be a non-zero number, in which case we get a YES. Insufficient.

From F.S 2, we know that xy>0. Thus, both x and y are non-zero numbers. Sufficient.

B.
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06 May 2013, 03:00
1
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Answer is B. for S1, the left side cannot be less than zero but certainly it can be zero if y = 0.

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06 May 2013, 03:22
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Good job guys!

The OA in indeed B.

$$|abs|$$ can be $$\geq{0}$$, so to make sure that is $$>$$ we need to enstablish that both x,y are $$\neq{0}$$

B does just that
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08 May 2013, 13:37
Zarrolou wrote:
Is 2|xy^2|> 0?

(1) x > 0

(2) xy > 0

Absolute values are always greater than equal to zero. So, the question is asking if both x and y are not zero.
1)No mention of y .
2)Both are positive or negative but not zero. That's what we want to know. SUFFICIENT.

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16 May 2013, 09:22
Zarrolou wrote:
Is 2|xy^2|> 0?

(1) x > 0

(2) xy > 0

Stmt 1 is not sufficient,
consider stmt2: sy is positive so no matter what ever may be the value of x, its in mod so its positive :: sufficient.

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23 Jun 2013, 08:38

If we open the modulus we arrive at different values

for xy > 0

x < 0, y < 0 then xy^2 < 0
x > 0, y > 0 then xy^2 > 0

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23 Jun 2013, 08:45
shivdeepmodi wrote:

If we open the modulus we arrive at different values

for xy > 0

x < 0, y < 0 then xy^2 < 0
x > 0, y > 0 then xy^2 > 0

No matter what sign $$xy^2$$ has, when we apply the mod it will become positive.

There is only one case in which this does not happen, and it's the case where $$xy=0$$ => $$|xy^2|=0$$.
With option B we are sure that neither x nor y is zero, so the expression $$2|xy^2|$$ will be positive.

There is no need to open the abs value, all we need to check is whether x and y are not zero numbers => B does that and it's sufficient.

Hope it's clear
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15 Sep 2013, 17:40
Since there's an absolute value symbol in the question, the ONLY time the left side ISN'T > 0 is when it EQUALS 0

So, if x or y = 0, then the answer is NO
If neither x nor y = 0, then the answer is YES

1) x > 0

x is positive, but we don't know about y
If y = 0, then NO
If y = anything else, then YES
Insufficient

2) xy > 0

x and y are either both positive or both negative. Neither can be 0 so the answer is always YES
Sufficient

Choose
[Reveal] Spoiler:
B

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01 Nov 2014, 16:35
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22 Mar 2017, 11:08
Hello from the GMAT Club BumpBot!

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Re: Is 2|xy^2|> 0?   [#permalink] 22 Mar 2017, 11:08
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