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Is 2y+3x−5=0 the equation of line q? (1) The x-intercept of line q?

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Is 2y+3x−5=0 the equation of line q? (1) The x-intercept of line q? [#permalink]

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New post Updated on: 07 Jun 2015, 07:12
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D
E

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58% (00:54) correct 42% (00:40) wrong based on 193 sessions

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Is 2y+3x−5=0 the equation of line q?

(1) The x-intercept of line q is (5,0).

(2) The slope of line q is 2/3.

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Originally posted by reto on 02 Jun 2015, 12:30.
Last edited by Bunuel on 07 Jun 2015, 07:12, edited 1 time in total.
Edited the OA.
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Re: Is 2y+3x−5=0 the equation of line q? (1) The x-intercept of line q? [#permalink]

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New post 07 Jun 2015, 06:37
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Hi! I'm new to your forum, so could you please explain, am I getting something wrong:
(1) The x-intercept of line q is (5,0): the x-intercept of the line above is (5/3;0). So it's sufficient to say that the equation does not apply to q;
(2) The slope of line q is 2/3: the slope of the line based on equation is 3/2. So is' also sufficient to say that the equation does not apply to q;

Therefore, my answer D differs from the official E. Am I wrong?
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Re: Is 2y+3x−5=0 the equation of line q? (1) The x-intercept of line q? [#permalink]

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New post 07 Jun 2015, 07:02
1
sVn91 wrote:
Hi! I'm new to your forum, so could you please explain, am I getting something wrong:
(1) The x-intercept of line q is (5,0): the x-intercept of the line above is (5/3;0). So it's sufficient to say that the equation does not apply to q;
(2) The slope of line q is 2/3: the slope of the line based on equation is 3/2. So is' also sufficient to say that the equation does not apply to q;

Therefore, my answer D differs from the official E. Am I wrong?


Hello There,

The same situation for me!

I translate the equation of the question into: Y=(-3X +5)/2

Statement 1: Allow us to try the point (5,0) into this equation.
so in the end we have 0=-5, so the equation above is not the equation of the line. Sufficient

Statement 2:
It looks to me that the slope of the equation is -3/2, so is different from the proposed in statement 2.
Also sufficient, hence D

Am I Wrong?
Experts, would you help us here?
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Re: Is 2y+3x−5=0 the equation of line q? (1) The x-intercept of line q? [#permalink]

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New post 07 Jun 2015, 07:12
pedrotupy wrote:
sVn91 wrote:
Hi! I'm new to your forum, so could you please explain, am I getting something wrong:
(1) The x-intercept of line q is (5,0): the x-intercept of the line above is (5/3;0). So it's sufficient to say that the equation does not apply to q;
(2) The slope of line q is 2/3: the slope of the line based on equation is 3/2. So is' also sufficient to say that the equation does not apply to q;

Therefore, my answer D differs from the official E. Am I wrong?


Hello There,

The same situation for me!

I translate the equation of the question into: Y=(-3X +5)/2

Statement 1: Allow us to try the point (5,0) into this equation.
so in the end we have 0=-5, so the equation above is not the equation of the line. Sufficient

Statement 2:
It looks to me that the slope of the equation is -3/2, so is different from the proposed in statement 2.
Also sufficient, hence D

Am I Wrong?
Experts, would you help us here?


The OA is D, not E. Edited. Thank you.
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Re: Is 2y+3x−5=0 the equation of line q? (1) The x-intercept of line q? [#permalink]

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New post 03 Mar 2017, 11:03
reto wrote:
Is 2y+3x−5=0 the equation of line q?

(1) The x-intercept of line q is (5,0).

(2) The slope of line q is 2/3.



Based on the question, we need to verify whether the given options 1 and 2 are sufficient to answer the question.

For 1) x-intercept of line q is (5,0) i.e 2(0) + 3(5) - 5 == 0? No. Sufficient to answer the point does not exist on the line.

For 2) the slope of line q, 2/3, is perpendicular the line provided. Hence, the equation 2y + 3x - 5 is not the equation for line q. Sufficient.

D
Re: Is 2y+3x−5=0 the equation of line q? (1) The x-intercept of line q?   [#permalink] 03 Mar 2017, 11:03
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