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Is 5^n < 0.04?

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Is 5^n < 0.04?  [#permalink]

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New post 20 Oct 2014, 06:59
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Question Stats:

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Re: Is 5^n < 0.04?  [#permalink]

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New post 20 Oct 2014, 22:15
Is 5^n < 0.04?

(1) (1/5)^n > 25
(2) n^3 < n^2[/quote]

Notice that for \(n\geq{0}\) so RHS of the Q stem is always greater than zero so we need to confirm whether n<-2 because\(5^{-2}\) is 1/25 =0.04

St 1 says (1/5)^n > 25 or n>2 so st 1 is sufficient as n is positive

St 2 says n^3<n^2 or n(n^2-1)<0 or n(n-1)(n+1) <0
Key points are n=0,-1 and 1

So we have 4 range

Case 1: n<-1 The expression n(n-1)(n+1) <0 is true
Case 2: -1<n<0, The expression is is false as it will be >0
Case3 : 0<n<1, The expression will be true
and Case 4: n>1 The expression will be true for all values

Since, we have 2 ranges in which expression holds true and for those range n <-2 or n>-2..

Ans is A
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Is 5^n < 0.04?  [#permalink]

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New post 28 Aug 2015, 14:38
WoundedTiger wrote:
Is 5^n < 0.04?

(1) (1/5)^n > 25
(2) n^3 < n^2


Notice that for \(n\geq{0}\) so RHS of the Q stem is always greater than zero so we need to confirm whether n<-2 because\(5^{-2}\) is 1/25 =0.04

St 1 says (1/5)^n > 25 or n>2 so st 1 is sufficient as n is positive

St 2 says n^3<n^2 or n(n^2-1)<0 or n(n-1)(n+1) <0
Key points are n=0,-1 and 1

So we have 4 range

Case 1: n<-1 The expression n(n-1)(n+1) <0 is true
Case 2: -1<n<0, The expression is is false as it will be >0
Case3 : 0<n<1, The expression will be true
and Case 4: n>1 The expression will be true for all values

Since, we have 2 ranges in which expression holds true and for those range n <-2 or n>-2..

Ans is A[/quote]
I think red part is wrong as It should be n<-2 for statement 1
For statement 2 it comes down to n^3-n^2<0----> n^2(n-1)<0 SO for sure n-1<0 as n^2 can't be less than 0 which becomes n<1 excluding n=0, with this we can't be sure is n<-2 always.
Correct me if I am Wrong
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Is 5^n < 0.04?  [#permalink]

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New post 29 Aug 2015, 05:12
Here is my approach:

Statement 1:
\(\frac{1}{5}^n > 25\)
\(5^-n > 5^2\)
\(-n > 2\)
\(n < -2\)

plug in n=-3 into the equation will yield that 1/125 is < than 0,04

Sufficient

Statement 2:
per statement n can be either a negative number or a proper fraction. 5^(1/2) would be > 0,04 while to a negative power would be <. not sufficient.

--> A
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Is 5^n < 0.04?  [#permalink]

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New post 27 Jan 2019, 07:35
Bunuel wrote:

Tough and Tricky questions: Absolute Values.



Is 5^n < 0.04?

(1) (1/5)^n > 25
(2) n^3 < n^2



Hi gmatbusters, Can you please share your thoughts on inline approach.

Is this a validate approach ??

is 5^n < 5^-2
becomes is n < -2 ??

1) 5^(-n) > 5^2
=> -n > 2
=> n < -2
Sufficient

2) Can't tell anything from this.
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Re: Is 5^n < 0.04?  [#permalink]

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New post 27 Jan 2019, 19:49
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Hii

Your approach to use first statement is correct.

For second statement.
n^3 < n^2
n^2(n-1)<0
n < 1
But since now n can be < or > -2, statement 2 is not sufficient

Hence Answer - A

KanishkM wrote:
Bunuel wrote:

Tough and Tricky questions: Absolute Values.



Is 5^n < 0.04?

(1) (1/5)^n > 25
(2) n^3 < n^2



Hi gmatbusters, Can you please share your thoughts on inline approach.

Is this a validate approach ??

is 5^n < 5^-2
becomes is n < -2 ??

1) 5^(-n) > 5^2
=> -n > 2
=> n < -2
Sufficient

2) Can't tell anything from this.

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Re: Is 5^n < 0.04?  [#permalink]

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New post 04 Apr 2019, 03:32
Bunuel wrote:

Tough and Tricky questions: Absolute Values.



Is 5^n < 0.04?

(1) (1/5)^n > 25
(2) n^3 < n^2


Question : Is \(5^n < 0.04\) ?

Or Is \(5^n < \frac{4}{100}\) ?

Or Is \(5^n < 5^{-2}\) ?

Finally, Is \(n < -2\) ?

Statement 1 : \(\frac{{1^n}}{{5}^n} > 25\)

Or 5\(^{-n} > 5^2\)

Or \(-n > 2\)

Or \(n < -2\) (Answer to the question, YES) SUFFICIENT

Statement 2 :

\(n^3 < n^2\) (As \(n^2\) will always be positive, divide both sides by n^2)

We get, n < 1

If \(n = 0\), the answer to the question is NO

If \(n = - 3\), the answer to the question is YES

NOT SUFFICIENT
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Re: Is 5^n < 0.04?   [#permalink] 04 Apr 2019, 03:32
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