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Is a < 0? (1) b^2 a > 0 (2) ab^2 < 0
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Bunuel
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Is a < 0? (1) b^2 a > 0 (2) ab^2 < 0 [#permalink] New post  24 May 2022, 00:40
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Is \(a < 0\)?

(1) \(b^2 – a > 0\)

(2) \(ab^2 < 0\)
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Re: Is a < 0? (1) b^2 a > 0 (2) ab^2 < 0 [#permalink] New post  24 May 2022, 01:13
(1) \(b^2–a>0\)
=> \(b^2 > a\)
We do not know value of 'b', so a can be +ve or -ve or 0. e.g., If b=2 then 'a' should be < 4 and 'a' can be -1, 0, 1, etc.
Statement 1 alone is not sufficient.

(2) \(ab^2<0\)
=> Square of a real number is always non-negative. Hence, \(b^2\) will always be >= 0
Product of \(a\) and \(b^2\) is -ve, implies 'b' is not equal to zero and 'a' is negative.
Statement 2 alone is sufficient.

Answer: B
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Re: Is a < 0? (1) b^2 a > 0 (2) ab^2 < 0 [#permalink]
24 May 2022, 01:13
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