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Re: Is |a^2 - b^2| < 10? (1) |a - b| < 5 (2) |a + b| < 2 [#permalink]
Could I seperate the equation |(a+b)(a-b)|<10 as |a+b|*|a-b|<10?
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Re: Is |a^2 - b^2| < 10? (1) |a - b| < 5 (2) |a + b| < 2 [#permalink]
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tinalongmao wrote:
Could I seperate the equation |(a+b)(a-b)|<10 as |a+b|*|a-b|<10?


Yes, you could.

Remember, Product and Division in absolute values could be separated.

I mean if we have |a/b|, we can write it as |a|/|b|

or |a*b|=|a|*|b|
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Re: Is |a^2 - b^2| < 10? (1) |a - b| < 5 (2) |a + b| < 2 [#permalink]
MathRevolution wrote:
Is |a^2-b^2|<10?
1) |a-b|<5
2) |a+b|<2

*An answer will be posted in 2 days.


I am struggling on this one. I understand that Statement 1 and Statement 2 are Not Sufficient. But I am not sure how to combine them algebraically and solve for statement 1 and statement 2 together. Can someone please show how to do this or an easier way to solve this?

Thanks,
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Re: Is |a^2 - b^2| < 10? (1) |a - b| < 5 (2) |a + b| < 2 [#permalink]
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msurls wrote:
MathRevolution wrote:
Is |a^2-b^2|<10?
1) |a-b|<5
2) |a+b|<2

*An answer will be posted in 2 days.


I am struggling on this one. I understand that Statement 1 and Statement 2 are Not Sufficient. But I am not sure how to combine them algebraically and solve for statement 1 and statement 2 together. Can someone please show how to do this or an easier way to solve this?

Thanks,


Is |a^2 - b^2| < 10?


(1) |a - b| < 5.

If a = b = 0, then the answer to the question is YES.
If a = 4 and b = 0, then the answer to the question is NO.

Not sufficient.


(2) |a + b| < 2

If a = b = 0, then the answer to the question is YES.
If a = 10 and b = -9, then the answer to the question is NO.

Not sufficient.


(1)+(2) Notice that |xy| = |x|*|y|, so the question asks whether |a^2 - b^2| = |(a - b)(a + b)| = |a - b|*|a + b| is less than 10. From (1) we have that 0 <= |a - b| < 5 and From (2) we have that 0 <= |a + b| < 2. Their product will be less than 10: 0 <= |a - b|*|a + b| < 10. Sufficient.


Answer: C.

Hope it's clear.
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Is |a^2 - b^2| < 10? (1) |a - b| < 5 (2) |a + b| < 2 [#permalink]
Bunuel wrote:
msurls wrote:
MathRevolution wrote:
Is |a^2-b^2|<10?
1) |a-b|<5
2) |a+b|<2

*An answer will be posted in 2 days.


I am struggling on this one. I understand that Statement 1 and Statement 2 are Not Sufficient. But I am not sure how to combine them algebraically and solve for statement 1 and statement 2 together. Can someone please show how to do this or an easier way to solve this?

Thanks,


Is |a^2 - b^2| < 10?


(1) |a - b| < 5.

If a = b = 0, then the answer to the question is YES.
If a = 4 and b = 0, then the answer to the question is NO.

Not sufficient.


(2) |a + b| < 2

If a = b = 0, then the answer to the question is YES.
If a = 10 and b = -9, then the answer to the question is NO.

Not sufficient.


(1)+(2) Notice that |xy| = |x|*|y|, so the question asks whether |a^2 - b^2| = |(a - b)(a + b)| = |a - b|*|a + b| is less than 10. From (1) we have that 0 <= |a - b| < 5 and From (2) we have that 0 <= |a + b| < 2. Their product will be less than 10: 0 <= |a - b|*|a + b| < 10. Sufficient.


Answer: C.

Hope it's clear.


Can we write |xy| = |x|*|y|, isn't it fundamentally wrong
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Re: Is |a^2 - b^2| < 10? (1) |a - b| < 5 (2) |a + b| < 2 [#permalink]
Expert Reply
cruiseav wrote:
We cannot write |xy| = |x|*|y|, it is fundamentally wrong


We can always do so. It is absolutely correct.

Check my comments here: https://gmatclub.com/forum/is-a-2-b-2-1 ... l#p1711648
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Re: Is |a^2 - b^2| < 10? (1) |a - b| < 5 (2) |a + b| < 2 [#permalink]
Expert Reply
cruiseav wrote:
Bunuel wrote:
msurls wrote:
I am struggling on this one. I understand that Statement 1 and Statement 2 are Not Sufficient. But I am not sure how to combine them algebraically and solve for statement 1 and statement 2 together. Can someone please show how to do this or an easier way to solve this?

Thanks,


Is |a^2 - b^2| < 10?


(1) |a - b| < 5.

If a = b = 0, then the answer to the question is YES.
If a = 4 and b = 0, then the answer to the question is NO.

Not sufficient.


(2) |a + b| < 2

If a = b = 0, then the answer to the question is YES.
If a = 10 and b = -9, then the answer to the question is NO.

Not sufficient.


(1)+(2) Notice that |xy| = |x|*|y|, so the question asks whether |a^2 - b^2| = |(a - b)(a + b)| = |a - b|*|a + b| is less than 10. From (1) we have that 0 <= |a - b| < 5 and From (2) we have that 0 <= |a + b| < 2. Their product will be less than 10: 0 <= |a - b|*|a + b| < 10. Sufficient.


Answer: C.

Hope it's clear.


Can we write |xy| = |x|*|y|, isn't it fundamentally wrong


Yes, we can. Why do you say that? In mathematics it's called multiplicativity: |xy| = |x|*|y| is true for all numbers x and y.
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Re: Is |a^2 - b^2| < 10? (1) |a - b| < 5 (2) |a + b| < 2 [#permalink]
st.1 distance of a from b is 5 --- they could be any number in the number line
st.2 distance of a from -b is 2 --- they could be any number in number line

when taken together only a set of values will satisfy the conditions that a is at distance 2 from -b and a distance 5 from b.

am i doing this right Bunuel?
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Re: Is |a^2 - b^2| < 10? (1) |a - b| < 5 (2) |a + b| < 2 [#permalink]
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