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# Is |a| > |b|? (1) b < -a (2) a < 0

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Senior Manager
Joined: 02 Sep 2006
Posts: 253

Kudos [?]: 74 [0], given: 0

Is |a| > |b|? (1) b < -a (2) a < 0 [#permalink]

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23 Mar 2007, 22:18
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Is |a| > |b|?

(1) b < -a

(2) a < 0

Kudos [?]: 74 [0], given: 0

Manager
Joined: 16 Dec 2005
Posts: 60

Kudos [?]: 6 [0], given: 0

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23 Mar 2007, 22:49
St 1 :
if a is a +ve number. mod. b > mod. a
But if a is a -ve number ...-a will be positive
so b< -a can be any number less than the positive integer -a ..i.e can be number between -a and +a and also beyond +a (i.e -ve ) ...so mod b can be less than or greater than mod a .

st 2 ..by itself isn't enough

Combining 1,2 ----Gives only that a is -ve..the exact range in which b lies viz., if it is between 0 and a (-ve value ) or is still lesser than a .

So E

Kudos [?]: 6 [0], given: 0

Senior Manager
Joined: 20 Feb 2007
Posts: 256

Kudos [?]: 63 [0], given: 0

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23 Mar 2007, 23:31

What is OA?

I just drew a number line and picked the numbers....

Kudos [?]: 63 [0], given: 0

Director
Joined: 14 Jan 2007
Posts: 775

Kudos [?]: 179 [0], given: 0

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24 Mar 2007, 06:19
IMO the answer is 'E',
take numbers a = -3, b=-4 these satisfy b< -a and a<0> |a| < |b|
now take a=-3, b =1, satisfy b<-a and a<0> |a| > |b|.

Hence both the stmts taken together are not suff.

Last edited by vshaunak@gmail.com on 24 Mar 2007, 06:22, edited 1 time in total.

Kudos [?]: 179 [0], given: 0

24 Mar 2007, 06:19
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# Is |a| > |b|? (1) b < -a (2) a < 0

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