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# Is |a| > |b|? (1) b < -a (2) a < 0

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Director
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Is |a| > |b|? (1) b < -a (2) a < 0 [#permalink]

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28 Apr 2008, 08:38
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is |a| > |b|?

(1) b < -a

(2) a < 0
Director
Joined: 01 May 2007
Posts: 793
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28 Apr 2008, 09:17
Incorrect. Can you show how to solve this algebraically?
SVP
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28 Apr 2008, 09:21
jimmyjamesdonkey wrote:
Is |a| > |b|?

(1) b < -a

(2) a < 0

I like E

b = 0 and a = -1 yields true

b= -4 and a = -3 yields false
Director
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28 Apr 2008, 09:28
OA is E. Manhattan solved by picking numbers...but I'd like to solve this by algebra is possible.
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28 Apr 2008, 10:51
I am sorry. I read the choices wrong in hurry. Ans will be C when a>0
Lemme give my solution for E without using numbers.

I use number line.

|b|<|a| when b lies between -a and a

<-----------b------------>
-------------------------------|------------|------------|---------------
-a 0 a

Combining the 2 statements gives me

to infinity<--------------------------------b------------>
-------------------------------|------------|------------|---------------
a 0 -a

Hope I am clear enough.

Now, if a had been greater than 0, the situation would have been

to infinity<---------b--------->
-------------------------------|------------|------------|---------------
-a 0 a
Intern
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28 Apr 2008, 10:59
Formatting got screwed up. I created a jpg file for the same. Have a look
Attachments

untitled.JPG [ 58.2 KiB | Viewed 723 times ]

Director
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28 Apr 2008, 11:23
thanks itsme291...but is there anyway to translate those number lines to algebra?
Intern
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28 Apr 2008, 11:39
The algebraic equations are already in front of you. Number line is used to make sense out of them.

I just created the equations given in the question to number line. Converting from number-line to algebraic form will give the same equations
Re: Manahattan GMAT Inequality   [#permalink] 28 Apr 2008, 11:39
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