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just not getting absolutes. Please can some one help in understanding this topic better.

This question can be very easily solved with number line approach.

Is |a| > |b|?

If we rephrase the question we'll get: on the number line does point \(a\) lie further from zero than point \(b\)? Note that we are not interested in the signs of \(a\) and \(b\).

(1) b < -a --> \(b+a<0\), the sum of two numbers is less than zero. Now, if both numbers are negative (to the left of zero) than their sum will obviously be less than zero, and any from these two could be further from zero, thus this statement is not sufficient.

(2) a < 0. Clearly insufficient.

(1)+(2) Example from (1) is still valid (we considered \(a<0\) in it, so 2 is satisfied), thus even taken together statements are not sufficient.

Im having trouble understanding the first statement. if b< -a , then you cant have that a is grater then b?

you haven have a 5 for b, and a has to be negative? or is it that you can enter a negative A and with the negative in the statement it changes it to a positive??

5<- (-10)

we would get 5<10 and that is true... for the statemnte

and the same thing can go for -5<-(-1) you would get -5<1 and that is true for statement one but contradicts the above and you can go take of A and D , and statement two is wrong that is why you get at E...

Re: Is |a| > |b|? (1) b < -a (2) a < 0 [#permalink]

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15 Feb 2013, 02:20

Bunuel, This is a very silly question. Kindly pardon me, when i approached this Q i chose (A) b < -a is the same as -a > b which means lal > lbl right ?

And another doubt, when do u substitute values for Inequalities / Solve the inequality / use the number line. I am very naive in using the number line so .. kindly mention when to use which approach.

Bunuel, This is a very silly question. Kindly pardon me, when i approached this Q i chose (A) b < -a is the same as -a > b which means lal > lbl right ?

And another doubt, when do u substitute values for Inequalities / Solve the inequality / use the number line. I am very naive in using the number line so .. kindly mention when to use which approach.

Thanks

Yes, \(-a > b\) is the same as \(b < -a\), but it does NOT mean that \(|a| > |b|\). Consider: \(a=-1\) and \(b=-2\) --> \(-a=1>-2=b\) but \(|a|=1<2=|b|\).

As for your other question: it really depends on the particular problem at hand and personal preferences to choose which approach to take.
_________________

Re: Is |a| > |b|? (1) b < -a (2) a < 0 [#permalink]

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09 May 2013, 22:55

Bunuel wrote:

thinktank wrote:

Bunuel, This is a very silly question. Kindly pardon me, when i approached this Q i chose (A) b < -a is the same as -a > b which means lal > lbl right ?

And another doubt, when do u substitute values for Inequalities / Solve the inequality / use the number line. I am very naive in using the number line so .. kindly mention when to use which approach.

Thanks

Yes, \(-a > b\) is the same as \(b < -a\), but it does NOT mean that \(|a| > |b|\). Consider: \(a=-1\) and \(b=-2\) --> \(-a=1>-2=b\) but \(|a|=1<2=|b|\).

As for your other question: it really depends on the particular problem at hand and personal preferences to choose which approach to take.

@Bunuel

I have this doubt:

b<-a...let say a= -3 and b=-5, (as given b<-a..it means b is also negative.). so mod of b> mod of a...hence A is suff. ?

Bunuel, This is a very silly question. Kindly pardon me, when i approached this Q i chose (A) b < -a is the same as -a > b which means lal > lbl right ?

And another doubt, when do u substitute values for Inequalities / Solve the inequality / use the number line. I am very naive in using the number line so .. kindly mention when to use which approach.

Thanks

Yes, \(-a > b\) is the same as \(b < -a\), but it does NOT mean that \(|a| > |b|\). Consider: \(a=-1\) and \(b=-2\) --> \(-a=1>-2=b\) but \(|a|=1<2=|b|\).

As for your other question: it really depends on the particular problem at hand and personal preferences to choose which approach to take.

@Bunuel

I have this doubt:

b<-a...let say a= -3 and b=-5, (as given b<-a..it means b is also negative.). so mod of b> mod of a...hence A is suff. ?

One example is NOT enough to say that a statement is sufficient.

Consider a=-5 and b=-3, to get the different answer.
_________________

This question can be solved best on number line. Is |a| > |b|? a and b can take any sign. (1) b < -a If a is positive -----------0---------a------- -=> b<-(a) --(b)-<--(-a)-----0-----a------ |b|>|a| Sufficient to say NO. If a is negative ---(-a)------0----------- -=> b<-(-a) => b<a --b----(-a)----b-----0---b----a------- b can be anywhere less than a. Not Sufficient to tell distance of b from origin compared to a, thus Option 1 Insufficient.

(2) a < 0 Clearly insufficient as we do not know anything about position of b.

Option 1 and 2 together, a is negative ---(-a)------0----------- -=> b<-(-a) => b<a --b----(-a)----b-----0---b----a------- b can be anywhere less than a. can not tell position of b comparative to a. Insufficient.

Ans E.
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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
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