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Zero divided by a negative or positive number is either zero or is expressed as a fraction with zero as numerator and the finite quantity as denominator.

Statement two says that a*c <0 so one of the numbers must be negative, all could be negative as well:

-8 * -6 * -4 = -192 which is divisible by 32 as per GMAT definition y=xq+r when q and r are unique integers and 0<=r<x ( -192=32*-6 + 0)

-6*-4*-2 =-48 which is not divisible by 32.

insufficient.

Taken together we have that they are consecutive, and that one is negative and the other is not. Because of the restriction of being consecutive and even we have only one possible set of numbers: -2,0,2.

abc =0. 0 is divisable by any integer except zero. so the answer was C.

tricky problem and I would have no doubt gotten this wrong on the test if i didn't have 10 minutes to sit and think about it

Statements (1) and (2) combined are sufficient. From S1 + S2 it follows that either a or c is negative. As a , b, and C are consecutive even integers, one of these three numbers must be 0. Thus, abc=0 which is divisible by 32

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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What..!!!!!! How No NO NO I have one question here => IF C is even and A is an integer then can A^C ever be negative. Extremely poor quality Question. And those explanations ????????

4 minutes wasted and that red flag popped out Damn Heartbreaking

What..!!!!!! How No NO NO I have one question here => IF C is even and A is an integer then can A^C ever be negative. Extremely poor quality Question. And those explanations ????????

4 minutes wasted and that red flag popped out Damn Heartbreaking

What..!!!!!! How No NO NO I have one question here => IF C is even and A is an integer then can A^C ever be negative. Extremely poor quality Question. And those explanations ????????

4 minutes wasted and that red flag popped out Damn Heartbreaking

What..!!!!!! How No NO NO I have one question here => IF C is even and A is an integer then can A^C ever be negative. Extremely poor quality Question. And those explanations ????????

4 minutes wasted and that red flag popped out Damn Heartbreaking

Guys Am i missing something here or this is an """ABSURD QUESTION"""

It's a multiplied by c, so a*c not a^c.

EDIT: NEVER MIND - Realize that the consecutive even integers makes that issue I was thinking of not matter...

Hey Bunuel I got this right a while back but a problem I have now that I'm reviewing is that the problem doesn't say a<b<c. I'm nervous about getting hung up on stuff like this if this is how it will appear on the actual test. Should I expect ambiguities like this?

1) States that a, b, c are consecutive even integer - it can be -2,2,4 or 2,4,6 (not divisible by 32) or 4,6,8 (divisible by 32) NOT sufficient 2) A*C<0 that means A is negative and C is positive or vice versa NOT sufficient

Combine both A,C, B = -2,2,4 ( A*B*C is not divisible by 32) SUFFICIENT! C answer

1) States that a, b, c are consecutive even integer - it can be -2,2,4or 2,4,6 (not divisible by 32) or 4,6,8 (divisible by 32) NOT sufficient 2) A*C<0 that means A is negative and C is positive or vice versa NOT sufficient

Combine both A,C, B = -2,2,4 ( A*B*C is not divisible by 32) SUFFICIENT! C answer

Hi..

you are correct with your method and answer but two errors.. [1) a*b*c needs to be\(\geq{32]\).. Not necessary as 0 can also be one value of a*b*c 2) a,b,c are consecutive even integers so -2,2,4 is wrong.. it will be -2,0,2

and hence product a*b*c= -2*0*2=0 and o is div by all numbers because 0*any integer = 0
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Thanks for the follow up. However, I was told that 0 is neither even nor odd integer that is why I took 0 out.

chetan2u wrote:

satsurfs wrote:

a*b*c needs to be\(\geq{32]\) and divisble by 32.

1) States that a, b, c are consecutive even integer - it can be -2,2,4or 2,4,6 (not divisible by 32) or 4,6,8 (divisible by 32) NOT sufficient 2) A*C<0 that means A is negative and C is positive or vice versa NOT sufficient

Combine both A,C, B = -2,2,4 ( A*B*C is not divisible by 32) SUFFICIENT! C answer

Hi..

you are correct with your method and answer but two errors.. [1) a*b*c needs to be\(\geq{32]\).. Not necessary as 0 can also be one value of a*b*c 2) a,b,c are consecutive even integers so -2,2,4 is wrong.. it will be -2,0,2

and hence product a*b*c= -2*0*2=0 and o is div by all numbers because 0*any integer = 0

The question is to find whether a*b*c is divisible by 32.

Statement 1: a, b and c are consecutive even integers. We know 32=2^5. That is, to be divisible by 32 the numerator has to contain at least 2^5.

Case 1: Let's take values for a,b and c as 4,6 and 8 respectively. 4= 2^2 6= 2^1 *3 8=2^3 When we add all the powers of 2 and3 we get: (2^6 * 3^2)/2^5 This is divisible by 32. --> YES

Case 2: Let's take values for a,b and c as 2,4 and 6 respectively. 2=2^1 4=2^2 6=2^1 * 3^1 Which gives, (2^4 * 3^1)/2^5 This is not divisible by 32. --> NO As we get both YES and NO from statement 1, this is not sufficient.

Statement 2: a*c < 0 We are just given a*c is negative and nothing else is given about these numbers. Case 1: a,b and c can be -8,2 and 10 => (-8*2*10) is divisible by 32 --> YES Case 2: a,b and c can be -3,1,5 => (-3*1*5) is not divisible by 32 --> NO Thus statement 2 is insufficient.

Combining both, we have a,b and c are consecutive even integers and a*c<0. This means, a<0, b is equal to 0 (0 is even and these are consecutive even numbers) and c>0. We don't have to pick numbers and check as anything multiplied by 0 is equal to 0. Also, 0 is a multiple of every number. Thus, 0 is a multiple of 32. Therefore, a*b*c is divisible by 32.