Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Note that we are not told that a, b and c are integers.

Q: is \(a+b+c=even\)?

(1) \(a-c-b=even\), if the variables are integers then \(a+b+c\) will be even but if they are not: \(a=3.5\), \(b=1\), \(c=0.5\) --> \(a-c-b=2=even\), but \(a+b+c=5=odd\). Not sufficient.

(2) \(\frac{a-c}{b}=odd\). The same here: if the variables are integers then \(a+b+c\) will be even but if they are not: \(a=3.5\), \(b=1\), \(c=0.5\) --> \(\frac{a-c}{b}=3=odd\), but \(a+b+c=5=odd\). Not sufficient

(1)+(2) \(a+b+c\) may or may not be even (again if variables are integers: YES but if \(a=3.5\), \(b=1\), \(c=0.5\) answer is NO). Not sufficient.

Re: Is A+B+C even? 1) A-C-B is even 2) (A-C)/B is odd [#permalink]

Show Tags

16 Dec 2011, 22:49

E it is.

I tried to solve algebraically. However, I have a question.

If it were mentioned that all three numbers were integers, how would the answer change? How to figure this out algebraically? (Without having to pick numbers)
_________________

Re: Is A+B+C even? 1) A-C-B is even 2) (A-C)/B is odd [#permalink]

Show Tags

18 Dec 2011, 23:27

jitbec wrote:

E.

What is the point of mentioning just the answer that you figured out? The OA is already known. If you could provide an effective method to solve the problem, it would be highly appreciated.

Re: Is A+B+C even? 1) A-C-B is even 2) (A-C)/B is odd [#permalink]

Show Tags

18 Dec 2011, 23:43

Lucky2783 wrote:

i dont an algebric way to do it but here is a simple permutation on A,B,C "if given is that A, B , C are integers" .

then option 1 A-B-C is even only in below cases A-C-B E-E-E E-O-O (E=Even, O=Odd) O-O-E O-E-O in all cases A+ B +c will be even .

stmt 2: A-B/C is odd

A/C - B/C should be odd. E O O E

A/C can be even in both cases E/E or E/O eg: 4/2 or 6/3. B/C can be even in both cases E/E or E/O eg: 4/2 or 6/3.

in the same way we can do for Odd case .

i.e. this stmt is insuff.

Hi I am not quite clear about your explanation for statement 2. I think you have interchanged two of the variables too. Could you please elaborate? Would be grateful.

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

There’s something in Pacific North West that you cannot find anywhere else. The atmosphere and scenic nature are next to none, with mountains on one side and ocean on...

This month I got selected by Stanford GSB to be included in “Best & Brightest, Class of 2017” by Poets & Quants. Besides feeling honored for being part of...

Joe Navarro is an ex FBI agent who was a founding member of the FBI’s Behavioural Analysis Program. He was a body language expert who he used his ability to successfully...