nehakhetan88 and

NonPlusAnswer is E.

Statement 1 is not sufficient because "a" is negative we know, but coming back to question at hand that whether ab<0 lets consider this.

a is -ve but when b is +ve, we get ab<0

but when a is -ve and b is also -ve, then ab>0

So, Just because b^8 is +ve we cant comment on the nature of b. b can either be +ve or -ve.

Statement 2 is also not sufficient.

a + b^8 = 12. In this, we will have break points when b is 1 or 2 or -2 etc.

When b is 1, a is +ve but when b is -2, a is -ve. So even in this case we are not clear. Hence insufficient.

Taking Statement 1 and 2 together.

In this we rule out all the cases where a is +ve. Just take a -ve since thats what we got from statement 1.

Now, a can be -ve when b is 3, -3, 2, -10 etc.

Hence even after taking both the statements we cant tell whether ab is <0.

Hope it clears your queries.

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