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# Is ax = (7 + 5bx)/4

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Is ax = (7 + 5bx)/4  [#permalink]

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13 Feb 2016, 06:05
1
00:00

Difficulty:

25% (medium)

Question Stats:

78% (00:27) correct 22% (00:11) wrong based on 54 sessions

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Is $$ax = \frac{(7 + 5bx)}{4}$$ ?

(1) $$x(4a - 5b) = 7$$
(2) $$a = 1$$
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Re: Is ax = (7 + 5bx)/4  [#permalink]

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13 Feb 2016, 11:56
ax= (7+ 5 bx)/4
=> 4 ax = 7 + 5 bx
=> x(4a - 5b )=7

(1) x(4a−5b) = 7
Sufficient
(2) a=1
Not sufficient

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Re: Is ax = (7 + 5bx)/4  [#permalink]

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30 Sep 2018, 04:55
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Re: Is ax = (7 + 5bx)/4 &nbs [#permalink] 30 Sep 2018, 04:55
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