Is b < 0 ? (1) Integer b is a multiple of 13 (2) b^3 < 13

VERITAS PREP OFFICIAL SOLUTION:

E. The key to this problem is recognizing that b could equal 0. Statement 1 should clearly not be sufficient, as there are infinitely many negative multiples of 13 (including -13, -26, -130, etc., all providing the answer "yes") but also infinitely many positive values (13, 26, 130, etc., each providing the answer "no"). And statement 2 should also pretty clearly not be sufficient, as any negative number would satisfy the statement, but so would an integer like 1 or 2.

Taken together, you might think that the statements are sufficient, as statement 1 rules out b = 1 and b = 2. But what about 0? 0 is a multiple of 13 and when cubed it's less than 13, but it's also not negative. All other solutions are negative multiples of 13 (-13, -26, -130, etc.) all providing the answer "yes" but 0 provides the answer "no", meaning that the statements together are not sufficient.