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# Is integer y > 0?

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Is integer y > 0?  [#permalink]

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27 Jul 2016, 00:43
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35% (medium)

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68% (01:17) correct 32% (01:46) wrong based on 200 sessions

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Is integer y > 0?

(1) –(2 + y) > 0

(2) (2 + y)^2 > 0

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Re: Is integer y > 0?  [#permalink]

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27 Jul 2016, 03:50
It's A, since y should be less than 0 for the -(2+y)>0.

For ST2 ycan take either +ve or -ve y.

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Re: Is integer y > 0?  [#permalink]

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27 Jul 2016, 04:18
Bunuel wrote:
Is integer y > 0?

(1) –(2 + y) > 0

(2) (2 + y)^2 > 0

Statement 1:

–(2 + y) > 0
=> 2+y < 0
=> y<-2. Hence, A is sufficient.

Statement 2: whether y is +ve or -ve, this statement will always be positive. Hence , INSUFFICIENT.
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Re: Is integer y > 0?  [#permalink]

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27 Jul 2016, 06:44
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Bunuel wrote:
Is integer y > 0?

(1) –(2 + y) > 0

(2) (2 + y)² > 0

Target question: Is integer y GREATER THAN 0?

Statement 1: –(2 + y) > 0
Expand to get: –2 - y > 0
Add y to both sides to get: -2 > y
If y is LESS than -2, we can be certain that y is NEGATIVE.
This means we can conclude that y is definitely not greater than 0
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: (2 + y)² > 0
Hmmm, the square of some value is ALWAYS greater than or equal to zero. So, this statement doesn't seem to tell us much.
Since this statement doesn't FEEL sufficient, I'll TEST some values.
There are several values of y that satisfy statement 2. Here are two:
Case a: y = 1. Here, (2 + y)² = (2 + 1)² = 9, and 9 > 0. In this case, y is GREATER THAN 0
Case b: y = -1. Here, (2 + y)² = (2 + -1)² = 1, and 1 > 0. In this case, y is NOT greater than 0
Since we cannot answer the target question with certainty, statement 2 is NOT SUFFICIENT

Aside: For more on this idea of plugging in values when a statement doesn't feel sufficient, you can read my article: http://www.gmatprepnow.com/articles/dat ... lug-values

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Re: Is integer y > 0?  [#permalink]

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27 Jul 2016, 14:43
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Bunuel wrote:
Is integer y > 0?

(1) –(2 + y) > 0

(2) (2 + y)^2 > 0

(1) –(2 + y) > 0
2+y <0
y<-2. This means that y is not >0

Sufficient.

(2) (2 + y)^2 > 0
(2 + y) > 0
y>-2

so y can be -1, 0 , 1. Not sufficient.

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Re: Is integer y > 0?  [#permalink]

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13 Oct 2018, 19:52
Bunuel wrote:
Is integer y > 0?

(1) –(2 + y) > 0

(2) (2 + y)^2 > 0

(1) –(2 + y) > 0
2+y <0
y<-2. This means that y is not >0

Sufficient.

(2) (2 + y)^2 > 0
(2 + y) > 0
y>-2

so y can be -1, 0 , 1. Not sufficient.

For statement 2, we have (2+y)^2 > 0 and you have tested for the positive value of (2+y). Theoretically, do we need to test for (2+y)<0 also?
Re: Is integer y > 0?   [#permalink] 13 Oct 2018, 19:52
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