Bunuel wrote:

Tough and Tricky questions: Absolute Values.

Is |n| < 1 ?

(1) n^x - n < 0

(2) x^(-1) = -2

We need to find whether -1<n<1

St 1 says n^x-n <0 or n (n^x-1 -1)<0 We don't know the value of x so not sufficient

St 2 says 1/x=-2 or x=-1/2...So important question what is this got to do with -1<n<1 : not sufficient

Combining we see that \(\sqrt{n}-n<0\)

So we have \(\sqrt{n}(1-\sqrt{n})<0\)

We will have 2 cases

Case 1 \(\sqrt{n}>0\) and \(1-\sqrt{n}<0\) or\(\sqrt{n}>1\) or n^2>1 or n>1 or n<-1

Case 2\(\sqrt{n} <0\) but it is not possible as the lowest possible value of \(\sqrt{n}=0\) so we need not consider this case..

Thus ans is C

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