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# Is n an integer? n^2 is an integer sqrt(n) is an integer

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Director
Joined: 12 Jun 2006
Posts: 532

Kudos [?]: 162 [0], given: 1

Is n an integer? n^2 is an integer sqrt(n) is an integer [#permalink]

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26 Feb 2007, 01:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is n an integer?

n^2 is an integer
sqrt(n) is an integer

Kudos [?]: 162 [0], given: 1

Manager
Joined: 12 Feb 2006
Posts: 115

Kudos [?]: 80 [0], given: 0

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26 Feb 2007, 02:05
I'll give it a try.

I think it is B.

For A we don't know. Try 2 and 1.41 as examples of N^2 being an integer.

For B it says the sqrt(N) is an integer. Therefore N = an integer x an integer and this always results in an integer.

Kudos [?]: 80 [0], given: 0

SVP
Joined: 01 May 2006
Posts: 1794

Kudos [?]: 166 [0], given: 0

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26 Feb 2007, 02:11
Agree with bz9

Kudos [?]: 166 [0], given: 0

Director
Joined: 12 Jun 2006
Posts: 532

Kudos [?]: 162 [0], given: 1

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28 Feb 2007, 14:37
1.414214 works. Are there any other numbers that work too? Is there a way (ie equation) to prove this?

Kudos [?]: 162 [0], given: 1

Senior Manager
Joined: 18 Feb 2007
Posts: 253

Kudos [?]: 1 [0], given: 0

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28 Feb 2007, 14:59
ggarr wrote:
1.414214 works. Are there any other numbers that work too? Is there a way (ie equation) to prove this?

sqrt(5),sqrt(6),sqrt(7), or any other integer hat does not have a square root..

Kudos [?]: 1 [0], given: 0

Director
Joined: 12 Jun 2006
Posts: 532

Kudos [?]: 162 [0], given: 1

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28 Feb 2007, 15:01
Quote:
any other integer hat does not have a square root
thanks. I should've seen that.

Kudos [?]: 162 [0], given: 1

28 Feb 2007, 15:01
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