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# Is p+q >r+s 1.p>r+s 2.q>r+s

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Director
Joined: 08 Jul 2004
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Is p+q >r+s 1.p>r+s 2.q>r+s [#permalink]

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07 Sep 2004, 14:01
00:00

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Is p+q >r+s
1.p>r+s
2.q>r+s

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Manager
Joined: 02 Apr 2004
Posts: 222

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Location: Utrecht

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07 Sep 2004, 14:13
I think the answer is C.

st.1
p > r+s
r+s = 2 than p > 2, but we still donÂ´t know the value of q.

st.2
q > r+s
r+s = 2 than q > 2, but we still donÂ´t know the value of p.

Both statements together prove that p and q are more than r+s.

Please correct me if I am wrong.

Regards,

Alex

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Director
Joined: 05 May 2004
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Location: San Jose, CA

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07 Sep 2004, 16:17
saurya_s wrote:
Is p+q >r+s
1.p>r+s
2.q>r+s

Got C
either one or 2 is not sufficient if we plu in -ve nums for pqrs

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Intern
Joined: 02 Sep 2004
Posts: 42

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15 Sep 2004, 16:06

first and second statements insufficient.

Togther
let r+s = -10
p = -6
q = -6

p+q not greater than r+s gives a No answer, but we can easily pick numbers to get an Yes answer.

So, E.

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Senior Manager
Joined: 22 Feb 2004
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15 Sep 2004, 19:00
What a beauty scoobee. Yes E IT SHUD BE.

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Manager
Joined: 02 Apr 2004
Posts: 222

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Location: Utrecht

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16 Sep 2004, 05:13
Very nice indeed Scooby.

Regards,

Alex

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Director
Joined: 31 Aug 2004
Posts: 606

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16 Sep 2004, 07:21
(1)+(2) => p+q > 2(r+s)
question is "is 2(r+s) > r+s ?"
Yes if r+s >0
No if <0

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16 Sep 2004, 07:21
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