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# Is p+q > r+s?

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Director
Joined: 12 Jun 2006
Posts: 532

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14 Dec 2006, 18:53
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Is p+q > r+s?
1) p> r+s
2) q > r+s

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Manager
Joined: 28 Aug 2006
Posts: 243

Kudos [?]: 3 [0], given: 0

Location: Albuquerque, NM

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14 Dec 2006, 18:56
C

Each statement alone is insufficent as the sign of q in 1 and p in 2 is unknown, but you can deduce from two statements that

p + q > 2 (r +s)

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Director
Joined: 12 Jun 2006
Posts: 532

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14 Dec 2006, 19:28
Thanks.
Quote:
p + q > 2 (r +s)

Was the 2 intentional? If so, what's the significance?

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Senior Manager
Joined: 23 Jun 2006
Posts: 387

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14 Dec 2006, 21:55

take p=q=r=s=-4

then both 1&2 hold, but stem doesn't

take p=q=10 r=s=4
then 1&2 hold and stem also...

hence insufficient.

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Manager
Joined: 28 Aug 2006
Posts: 243

Kudos [?]: 3 [0], given: 0

Location: Albuquerque, NM

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01 Jan 2007, 23:26
ok can't add inequalities with same sign if only rhs is same (see Honhgu post)

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01 Jan 2007, 23:26
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