Hi,
Consider, 1. p^q=1
If p=10, q=0, then
=> p^q=1 (10^0=1)
=> pq > 1 is false (10*0 = 0 < 1)
If p=-1, q=-2, then
=> p^q=1 (-1^-2=1)
=> p^q > 1 true (-1*-2 = 2 > 1)
We have both true and false considering only first condition. Hence, A and D choices are eliminated.
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Now, consider 2. q=-1
If p=-2, then p^q>1
If p=2, then p^q<1
So, clearly only 2 is insufficient. Hence, B is eliminated.
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If p^q=1 and q=-1, then p=1.
Since p and q have definite values, 1. and 2. together are sufficient.
Hence, C is the answer.
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TH
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