GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 20 Apr 2019, 09:35

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Is r > s ?

Author Message
TAGS:

Hide Tags

Manager
Joined: 17 Nov 2009
Posts: 219
Is r > s ?  [#permalink]

Show Tags

01 Oct 2010, 08:58
2
00:00

Difficulty:

5% (low)

Question Stats:

82% (00:54) correct 18% (01:10) wrong based on 242 sessions

HideShow timer Statistics

Is r > s ?

(1) -r + s < 0
(2) r < | s |
Math Expert
Joined: 02 Sep 2009
Posts: 54376

Show Tags

01 Oct 2010, 09:03
1
agnok wrote:
Is r > s ?

(1) -r + s < 0
(2) r < | s |

Is $$r>s$$?

(1) $$-r+s<0$$ --> add $$r$$ to both parts --> $$s<r$$, directly answers the question. Sufficient.

(2) $$r<|s|$$ --> either $$r<s$$ or $$r<-s$$ (for example $$r=1$$ and $$s=2$$ OR $$r=1$$ and $$s=-2$$). Not sufficient.

_________________
Manager
Joined: 06 Nov 2009
Posts: 174
Concentration: Finance, Strategy

Show Tags

01 Oct 2010, 09:25
Answer A is correct, try to solve such problems by number plug-in
Current Student
Joined: 12 Aug 2015
Posts: 2613
Schools: Boston U '20 (M)
GRE 1: Q169 V154
Re: Is r > s ?  [#permalink]

Show Tags

13 Mar 2016, 06:57
HERE statement 1 is sufficient as we directly arrive at the result of r>s

statement 2 is insufficient as it tells us => s>r or s<-r => not sufficient
hence A is sufficient
_________________
Director
Joined: 04 Jun 2016
Posts: 564
GMAT 1: 750 Q49 V43
Re: Is r > s ?  [#permalink]

Show Tags

18 Jul 2016, 01:41
agnok wrote:
Is r > s ?

(1) -r + s < 0
(2) r < | s |

This is a yes or no question. Any value as long as it is definite yes or definite no will be correct
Is r > s ?
(1) -r + s < 0
r>s
Is r > s = YES
SUFFICIENT

(2) r < | s |
r<s or r<-s

First case
r<s
Is r > s NO

Second case
r <- s sometimes yes, sometimes no

Is 4 < -5 no
Is 4 < -(-5) yes

INSUFFICIENT

_________________
Posting an answer without an explanation is "GOD COMPLEX". The world doesn't need any more gods. Please explain you answers properly.
FINAL GOODBYE :- 17th SEPTEMBER 2016. .. 16 March 2017 - I am back but for all purposes please consider me semi-retired.
Intern
Joined: 23 Apr 2016
Posts: 21
Location: Finland
GPA: 3.65
Re: Is r > s ?  [#permalink]

Show Tags

24 Jul 2016, 06:49
2) r < |s|
doesn't it mean that r lies between s and -s -s < r < s ... so r definitely is smaller than s ?
Math Expert
Joined: 02 Sep 2009
Posts: 54376
Re: Is r > s ?  [#permalink]

Show Tags

24 Jul 2016, 08:02
thapliya wrote:
2) r < |s|
doesn't it mean that r lies between s and -s -s < r < s ... so r definitely is smaller than s ?

That's not correct.

(2) $$r<|s|$$ --> either $$r<s$$ or $$r<-s$$ (for example $$r=1$$ and $$s=2$$ OR $$r=1$$ and $$s=-2$$). Not sufficient.
_________________
BSchool Forum Moderator
Joined: 28 Mar 2017
Posts: 1211
Location: India
GMAT 1: 730 Q49 V41
GPA: 4
Re: Is r > s ?  [#permalink]

Show Tags

08 Jul 2017, 01:14
Bunuel wrote:
thapliya wrote:
2) r < |s|
doesn't it mean that r lies between s and -s -s < r < s ... so r definitely is smaller than s ?

That's not correct.

(2) $$r<|s|$$ --> either $$r<s$$ or $$r<-s$$ (for example $$r=1$$ and $$s=2$$ OR $$r=1$$ and $$s=-2$$). Not sufficient.

Bunuel, please correct my below understanding, if i am wrong:

Example: If we have an equation, |x| >1 it means simply x>1 or x<-1;

Coming back to the question, it states that s>r or s<-r
Case 1. s>r => r<s
Case 2. s<-r => -s>r => r<-s
combining the 2 cases we have r<-s;

Now in order for r<-s to be true we have further 2 cases:
s=+ve; then, r must be negative => s=1 then r<-1 clearly r is not greater than s
s=-ve; then, r can be wither + or -; s=-2 then r=1 or -3 in such case we don't know r>s or not. Hence it is insufficient to answer.

Is my reasoning correct?
_________________
Re: Is r > s ?   [#permalink] 08 Jul 2017, 01:14
Display posts from previous: Sort by