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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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Am confused about the official answer and thought of the short answer below.

i think like this

from 1

/r/<= s....insuff

from 2

/r/>=s...insuff

both /r/ = s.... insuff .... no info about r=s...E

Is this a right approach or not

Yes, absolutely fine.

Dear Karishma: How is he translating from: (1) -s<=r<=s to to: /r/>=s Do you have any helpful links for this topic? Im struggling heavily with it Thank you
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Dear Karishma: How is he translating from: (1) -s<=r<=s to to: /r/>=s Do you have any helpful links for this topic? Im struggling heavily with it Thank you

What is module: Module \(|r| = r\) than \(r > 0\) and \(|r| = -r\) than \(r < 0\) so \(|2| = 2\) and \(|-2| = 2\) (just for simplifying you can think about module as about dropping minus from number, but for harder tasks you should use operation described above)

And about our task: We can make example from this inequality \(−s≤r≤s\) --> \(-4 ≤ 2 ≤ 4\) or \(-4 ≤ -2 ≤ 4\) So this inequality will be true for \(r\) and for \(r *-1\)

So we can change \(r\) in this inequality on \(|r|\) and this inequality still be true --> \(-4 ≤ |2| ≤ 4\) And from this part we can drop left side of inequality and write it as \(|2| ≤ 4\)

Dear Karishma: How is he translating from: (1) -s<=r<=s to to: /r/>=s Do you have any helpful links for this topic? Im struggling heavily with it Thank you

What is module: Module \(|r| = r\) than \(r > 0\) and \(|r| = -r\) than \(r < 0\) so \(|2| = 2\) and \(|-2| = 2\) (just for simplifying you can think about module as about dropping minus from number, but for harder tasks you should use operation described above)

And about our task: We can make example from this inequality \(−s≤r≤s\) --> \(-4 ≤ 2 ≤ 4\) or \(-4 ≤ -2 ≤ 4\) So this inequality will be true for \(r\) and for \(r *-1\)

So we can change \(r\) in this inequality on \(|r|\) and this inequality still be true --> \(-4 ≤ |2| ≤ 4\) And from this part we can drop left side of inequality and write it as \(|2| ≤ 4\)

Hey Harley! Good to see you here! Thanks for your explanation - i really gotta study hard for that quant stuff! Thanks and all the best
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Saving was yesterday, heat up the gmatclub.forum's sentiment by spending KUDOS!

PS Please send me PM if I do not respond to your question within 24 hours.

Dear Karishma: How is he translating from: (1) -s<=r<=s to to: /r/>=s Do you have any helpful links for this topic? Im struggling heavily with it Thank you

I am guessing you have already got the logic of how -s<=r<=s translates to |r| <= s.

Keep these basic relations in mind:

|r| <= s implies -s <= r <= s

|r| >= s implies either r <= -s or r >= s

r, the term inside the absolute value could be anything.

|x - 4| <= 4 implies -4 <= x - 4 <= 4 Add 4 to the inequality to get: 0<= x <= 8 etc
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Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

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