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Is rs = rx − 2 ? (1) r is an odd number (2) x = s + 2

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Manager
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Joined: 17 Nov 2009
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Is rs = rx − 2 ? (1) r is an odd number (2) x = s + 2 [#permalink]

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New post 17 May 2010, 13:44
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A
B
C
D
E

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Question Stats:

67% (00:24) correct 33% (00:47) wrong based on 6 sessions

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Is rs = rx − 2 ?

(1) r is an odd number
(2) x = s + 2

OPEN DISCUSSION OF THIS QUESTION IS HERE: https://gmatclub.com/forum/is-rs-rx-158366.html

Kudos [?]: 59 [0], given: 17

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Joined: 25 Jun 2009
Posts: 298

Kudos [?]: 150 [0], given: 6

Re: Is rs = rx − 2 ? (1) r is an odd number (2) x = s + 2 [#permalink]

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New post 17 May 2010, 13:50
agnok wrote:
Is rs=rx-2?

1. r is odd
2. x=s+2

Answer B.


Is there some thing missing in this question ?

Anyway, Question is asking whether 2= rx-rs ?

1. Clearly insufficient

2. putting the value of x = > 2= rs + 2r -rs = > 2= 2r

which means the st 2 will be sufficient if we know that r =1 but else its not and hence answer should be E and not B

Kudos [?]: 150 [0], given: 6

Manager
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Joined: 17 Nov 2009
Posts: 235

Kudos [?]: 59 [0], given: 17

Re: Is rs = rx − 2 ? (1) r is an odd number (2) x = s + 2 [#permalink]

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New post 24 Jun 2010, 08:22
Thanks nitishmahajan! I see it

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Kudos [?]: 128872 [0], given: 12183

Re: Is rs = rx − 2 ? (1) r is an odd number (2) x = s + 2 [#permalink]

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New post 11 Aug 2017, 03:09
Is rs = rx − 2 ?

Is \(rs = rx-2\)? --> is \(r(x-s)=2\)?

(1) r is an odd number. Not sufficient: consider r=1 and x-s=2 AND r=1 and x-s=3.

(2) x = s + 2 -->\(x-s=2\) --> the question becomes: is \(r=1\)? We don't know that. Not sufficient.

(1)+(2) From (2) the question became: is \(r=1\)? and (1) says that r=odd, but we don't know whether it's 1 or any other odd number. Not sufficient.

Answer: E.

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Kudos [?]: 128872 [0], given: 12183

Re: Is rs = rx − 2 ? (1) r is an odd number (2) x = s + 2   [#permalink] 11 Aug 2017, 03:09
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