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Is the exact value of x/y less than 0.5? [#permalink]
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30 Dec 2013, 13:33
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Is the exact value of x/y less than 0.5? (1) When x and y are rounded to the nearest ten, x is 30, and y is 70. (2) When x and y are rounded to the nearest unit, x is 32, and y is 65.
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Re: Is the exact value of x/y less than 0.5? [#permalink]
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03 Jan 2014, 04:29
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teabecca wrote: Is the exact value of x/y less than 0.5?
(1) When x and y are rounded to the nearest ten, x is 30, and y is 70.
(2) When x and y are rounded to the nearest unit, x is 32, and y is 65. We need to find whether x/y<0.5 From St 1, we have Possible range of x = 25 to 35 Y = 65 to 75 Now the range of x/y will be between min x/max y and max x/min y> 25/75 and 35/65 Clearly the x<y can have value more or less than 0.5 A& D ruled out From St 2 we have Possible value of x 31.5 to 32.5 and for y = 64.5 to 65.5 31.5/65.5 <x/y< 32.5/65.5 Again it can value more than or less than 0.5 Combining we get that X is between 31.5 and 32.5 and Y is more than 65 (Y can have any value above 65 till 74.9999) and for all possible values of Y, X/Y will be less than 0.5 Ans C
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Re: Is the exact value of x/y less than 0.5? [#permalink]
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12 Jun 2014, 17:52
teabecca wrote: Is the exact value of x/y less than 0.5?
(1) When x and y are rounded to the nearest ten, x is 30, and y is 70.
(2) When x and y are rounded to the nearest unit, x is 32, and y is 65. statement 1 \(25 \leq x \leq 34\) \(65 \leq y \leq 74\) lowest value of x/y = 25/74 = 0.33 Highest Value of x/y = 34/65 = 0.52 Hence Insufficient Statement 2 = \(31.5 \leq x \leq 32.4\) \(64.5\leq x \leq 65.4\) Lowest value of x/y = 0.48 Highest value of x/y = 0.50 hence insufficient 1+ 2 Now can anybody explain how to get the value of x and y using both 1 and 2



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Re: Is the exact value of x/y less than 0.5? [#permalink]
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14 Jun 2014, 02:33
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qlx wrote: teabecca wrote: Is the exact value of x/y less than 0.5?
(1) When x and y are rounded to the nearest ten, x is 30, and y is 70.
(2) When x and y are rounded to the nearest unit, x is 32, and y is 65. statement 1 \(25 \leq x \leq 34\) \(65 \leq y \leq 74\) lowest value of x/y = 25/74 = 0.33 Highest Value of x/y = 34/65 = 0.52 Hence Insufficient Statement 2 = \(31.5 \leq x \leq 32.4\) \(64.5\leq x \leq 65.4\) Lowest value of x/y = 0.48 Highest value of x/y = 0.50 hence insufficient 1+ 2 Now can anybody explain how to get the value of x and y using both 1 and 2 Combine 1 and 2. \(31.5 \leq x \leq 32.4\) \(65 \leq y \leq 65.4\) => x/y < 32.4/65 < 32.5/65 = 1/2. Here you go!



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Re: Is the exact value of x/y less than 0.5? [#permalink]
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14 Jun 2014, 11:59
Icerockboom wrote: qlx wrote: teabecca wrote: Is the exact value of x/y less than 0.5?
(1) When x and y are rounded to the nearest ten, x is 30, and y is 70.
(2) When x and y are rounded to the nearest unit, x is 32, and y is 65. statement 1 \(25 \leq x \leq 34\) \(65 \leq y \leq 74\) lowest value of x/y = 25/74 = 0.33 Highest Value of x/y = 34/65 = 0.52 Hence Insufficient Statement 2 = \(31.5 \leq x \leq 32.4\) \(64.5\leq x \leq 65.4\) Lowest value of x/y = 0.48 Highest value of x/y = 0.50 hence insufficient 1+ 2 Now can anybody explain how to get the value of x and y using both 1 and 2 Combine 1 and 2. \(31.5 \leq x \leq 32.4\) \(65 \leq y \leq 65.4\) => x/y < 32.4/65 < 32.5/65 = 1/2. Here you go! Thanks Buddy , I see that we have to take the overlapping values of x from both statements and overlapping values of Y from Both statements.



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Re: Is the exact value of x/y less than 0.5? [#permalink]
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18 Jun 2014, 07:24
Isn't B a subset of A ?



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Re: Is the exact value of x/y less than 0.5? [#permalink]
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18 Jun 2014, 07:26
WoundedTiger wrote: teabecca wrote: Is the exact value of x/y less than 0.5?
(1) When x and y are rounded to the nearest ten, x is 30, and y is 70.
(2) When x and y are rounded to the nearest unit, x is 32, and y is 65. We need to find whether x/y<0.5 From St 1, we have Possible range of x = 25 to 35 Y = 65 to 75Now the range of x/y will be between min x/max y and max x/min y> 25/75 and 35/65 Clearly the x<y can have value more or less than 0.5 A& D ruled out From St 2 we have Possible value of x 31.5 to 32.5 and for y = 64.5 to 65.5 31.5/65.5 <x/y< 32.5/65.5 Again it can value more than or less than 0.5 Combining we get that X is between 31.5 and 32.5 and Y is more than 65 (Y can have any value above 65 till 74.9999) and for all possible values of Y, X/Y will be less than 0.5 Ans C Shouldn't the possible range be from 25 to 34 and 65 to 74 because the moment the number becomes 35 , it will round up to 40



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Re: Is the exact value of x/y less than 0.5? [#permalink]
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18 Jun 2014, 09:39
himanshujovi wrote: WoundedTiger wrote: teabecca wrote: Is the exact value of x/y less than 0.5?
(1) When x and y are rounded to the nearest ten, x is 30, and y is 70.
(2) When x and y are rounded to the nearest unit, x is 32, and y is 65. We need to find whether x/y<0.5 From St 1, we have Possible range of x = 25 to 35 Y = 65 to 75Now the range of x/y will be between min x/max y and max x/min y> 25/75 and 35/65 Clearly the x<y can have value more or less than 0.5 A& D ruled out From St 2 we have Possible value of x 31.5 to 32.5 and for y = 64.5 to 65.5 31.5/65.5 <x/y< 32.5/65.5 Again it can value more than or less than 0.5 Combining we get that X is between 31.5 and 32.5 and Y is more than 65 (Y can have any value above 65 till 74.9999) and for all possible values of Y, X/Y will be less than 0.5 Ans C Shouldn't the possible range be from 25 to 34 and 65 to 74 because the moment the number becomes 35 , it will round up to 40 Is the exact value of x/y less than 0.5?(1) When x and y are rounded to the nearest ten, x is 30, and y is 70: \(25 \leq x < 35\). \(65 \leq y < 75\). We can get x/y to be less than 1/2 as well as more than 1/2. Not sufficient. (2) When x and y are rounded to the nearest unit, x is 32, and y is 65: \(31.5\leq x < 32.5\). \(64.5 \leq y < 65.5\). We can get x/y to be less than 1/2 as well as more than 1/2. Not sufficient. (1)+(2) \(31.5\leq x < 32.5\) and \(65 \leq y < 65.5\). The minimum value of y (65) is more than twice as large as the maximum value of x (<32.5). So, x/y < 1/2. Sufficient. Answer: C.
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Re: Is the exact value of x/y less than 0.5? [#permalink]
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18 Jun 2014, 10:24
I agree on the answer. My query is around rounding concept
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Re: Is the exact value of x/y less than 0.5? [#permalink]
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Re: Is the exact value of x/y less than 0.5? [#permalink]
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18 Jun 2014, 13:49
I believe woundedtiger's solution had this problem
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