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Is the triangle depicted above equilateral? (1) x + y + z = 180° (2)

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Is the triangle depicted above equilateral? (1) x + y + z = 180° (2)  [#permalink]

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New post 27 Mar 2019, 06:54
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

95% (00:33) correct 5% (00:24) wrong based on 21 sessions

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Attachment:
XXDD.jpg
XXDD.jpg [ 5.27 KiB | Viewed 380 times ]
(Figure not necessarily drawn to scale.)

Is the triangle depicted above equilateral?

(1) \(x + y + z = 180°\)

(2) \(y = z\)

Source: McGraw-Hill's GMAT

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Re: Is the triangle depicted above equilateral? (1) x + y + z = 180° (2)  [#permalink]

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New post 27 Mar 2019, 07:27
Attachment:
XXDD.jpg
(Figure not necessarily drawn to scale.)

Is the triangle depicted above equilateral?

(1) \(x + y + z = 180°\)
This is the case for any triangle, so no new information at all.
Surely all choices containg statement I are out, so A, C and D are out

(2) \(y = z\)
We know the triangle is isosceles triangle, but it could be x=y=z. so Insuff
B is also out

Combined..
We have already eliminated C as possible answer

E
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Re: Is the triangle depicted above equilateral? (1) x + y + z = 180° (2)  [#permalink]

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New post 27 Mar 2019, 07:46
#1
x+y+z=180
no info whether its equilaterial, isosceles ∆ ; in sufficient
#2
y=z
so
x+2y=180
so ∆ can be isoscles or may not be in case x=y ; in sufficient
from1 & 2
we cannot derive any info
IMOE

SajjadAhmad wrote:
Attachment:
XXDD.jpg
(Figure not necessarily drawn to scale.)

Is the triangle depicted above equilateral?

(1) \(x + y + z = 180°\)

(2) \(y = z\)

Source: McGraw-Hill's GMAT
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Re: Is the triangle depicted above equilateral? (1) x + y + z = 180° (2)  [#permalink]

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New post 27 Mar 2019, 09:08
statement 1.

sum of all angles is 180 .

but it may be any triangle . insufficient


statement 2

y=z

insufficient .

Even if we combined these two,

we get ,

x+2y = 180 , we can not solve this equation to get unique values


Hence Option E

Neither of these is sufficient .

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Re: Is the triangle depicted above equilateral? (1) x + y + z = 180° (2)   [#permalink] 27 Mar 2019, 09:08
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