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Is the two-digit integer, with digits R and M (in that

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Is the two-digit integer, with digits R and M (in that [#permalink]

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02 Jan 2004, 19:21
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Is the two-digit integer, with digits R and M (in that order), a multiple of 7?

(1) R + M = 13

(2) R is divisible by 3

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02 Jan 2004, 21:31
I

1 is sufficient.

MR = 49/7
M+R=13

The only other options M+R = 13 are 67, 58, 94, 85, 76 none are divisile y 7

2 is extra statement

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03 Jan 2004, 07:40
C as well. 1 is not sufficient on it's own. True that 49 is divisible by 13 but so is 58 and the latter is not a multiple of 7. Both statements combined say that RM is definitely not a multiple of 7
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03 Jan 2004, 22:32
Where are u geeting the idea of 49 divisible by 13.

Only thing we know is MR is divisible by 7 - an dthe only number M+R=13 that is divisible by 7 is 49

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03 Jan 2004, 23:14
Oops, I meant that true that 49 (sum=13) is divisible by 7 but 58(sum=13) is not divisible by 7
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5 or E is the answer [#permalink]

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04 Jan 2004, 19:57
#1 - Insufficient; the only number that works is 49 but none of the others do.

#2 - Insufficient; only numbers valid are: 35, 63, 91 and 98 - but there are many more not divisible by 7

#3 - Insufficient; '4' in 49 is not divisible by three

Remember, this is a yes or no question. If is not possible for the statements to give you a definitive answer, then the statement is insufficient.

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04 Jan 2004, 20:33
mihir14, I believe your reasoning is wrong. Agree that each statement by itself is insufficient but both statements together can bring you to the conclusion that the answer is not a multiple of 7. Your exemple that 49 is not divisible by 3 is not appropriate because, precisely, 49 is not even divisible by 3 in the first place so it could not serve as exemple. The numbers whereby R+M = 13 are 49-94-58-85-67-76 and none of those are divisible by 3. Therefore, nevermind a multiple of 7, no number can satisfy those requirements and C conveys that
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04 Jan 2004, 20:33
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