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# Is the value of the perimeter of rectangle R greater than

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Manager
Joined: 18 Jun 2011
Posts: 58

Kudos [?]: 160 [0], given: 0

Is the value of the perimeter of rectangle R greater than [#permalink]

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19 Jun 2011, 23:20
00:00

Difficulty:

65% (hard)

Question Stats:

55% (16:02) correct 45% (01:06) wrong based on 75 sessions

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Is the value of the perimeter of rectangle R greater than the value of its area?

(1) The width of rectangle R is 2 inches.

(2) The area of rectangle R is 200 square inches.
[Reveal] Spoiler: OA

Kudos [?]: 160 [0], given: 0

Senior Manager
Joined: 30 Aug 2009
Posts: 283

Kudos [?]: 191 [1], given: 5

Location: India
Concentration: General Management

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20 Jun 2011, 04:32
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KUDOS
guygmat wrote:
Is the value of the perimeter of rectangle R greater than the value of its area?

(1) The width of rectangle R is 2 inches.

(2) The area of rectangle R is 200 square inches.

stmnt1 -
area = l*w = 2l
perimeter = 2[l+w] = 2l + 4. So perimeter is always greater than Area. hence Suff

stmnt2-
Area= l*w = 200
here l can be 20 and w= 10 giving perimeter as 2(20+10) = 60. So perimeter is less than Area

now lets consider l = 200 and w=1 giving Area = 200 and perimeter as 2(100+1) = 202. So perimeter value is greater than Area value.

Ans A

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Director
Joined: 29 Nov 2012
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Kudos [?]: 1454 [0], given: 543

Re: Is the value of the perimeter of rectangle R greater than [#permalink]

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20 Jul 2013, 05:48
Really Tricky! good question...
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Math Expert
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Re: Is the value of the perimeter of rectangle R greater than [#permalink]

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20 Jul 2013, 06:26
Is the value of the perimeter of rectangle R greater than the value of its area?

Is 2(L+W)>LW ?

(1) The width of rectangle R is 2 inches --> W=2. The question becomes: is 2(L+2)>2L? --> is 2>0? The answer is YES. Sufficient.

(2) The area of rectangle R is 200 square inches --> LW=200. The question becomes: is 2(L+W)>200? --> is L+W>100. We don't know that. Not sufficient.

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Re: Is the value of the perimeter of rectangle R greater than   [#permalink] 20 Jul 2013, 06:26
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