It is currently 17 Oct 2017, 04:50

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

Is |x|< 1? (1) |x + 1| = 2|x - 1| (2) |x - 3| ? 0

  post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
Senior Manager
Senior Manager
avatar
Joined: 08 Aug 2005
Posts: 251

Kudos [?]: 64 [0], given: 0

Is |x|< 1? (1) |x + 1| = 2|x - 1| (2) |x - 3| ? 0 [#permalink]

Show Tags

New post 01 Dec 2005, 00:32
00:00
A
B
C
D
E

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 1 sessions

HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is |x|< 1?
(1) |x + 1| = 2|x - 1|
(2) |x - 3| ≠ 0

Kudos [?]: 64 [0], given: 0

Intern
Intern
avatar
Joined: 01 Dec 2005
Posts: 3

Kudos [?]: [0], given: 0

 [#permalink]

Show Tags

New post 01 Dec 2005, 08:47
1. x1 = 3; x2=-3
---> insuff
2. x != 3
---> insuff

the answer is C
we discard x1 = 3
---> x = -3 < 1

Last edited by SG1 on 01 Dec 2005, 09:31, edited 2 times in total.

Kudos [?]: [0], given: 0

Director
Director
avatar
Joined: 24 Oct 2005
Posts: 659

Kudos [?]: 16 [0], given: 0

Location: London
 [#permalink]

Show Tags

New post 01 Dec 2005, 09:09
Ans = E.
Both statements not sufficient

Kudos [?]: 16 [0], given: 0

Senior Manager
Senior Manager
avatar
Joined: 05 Oct 2005
Posts: 485

Kudos [?]: 6 [0], given: 0

 [#permalink]

Show Tags

New post 07 Dec 2005, 15:31
Can you please explain why it is E?

Kudos [?]: 6 [0], given: 0

VP
VP
avatar
Joined: 22 Aug 2005
Posts: 1112

Kudos [?]: 121 [0], given: 0

Location: CA
 [#permalink]

Show Tags

New post 07 Dec 2005, 15:57
C.

S1: x = 3, 1/3; insufficient
S2: any thing except 3; insufficient

together: x = 1/3 < 1
_________________

Whether you think you can or think you can't. You're right! - Henry Ford (1863 - 1947)

Kudos [?]: 121 [0], given: 0

SVP
SVP
User avatar
Joined: 16 Oct 2003
Posts: 1798

Kudos [?]: 170 [0], given: 0

 [#permalink]

Show Tags

New post 07 Dec 2005, 18:47
C

1. X = 3 or -3
2. X<>3

Together 1. and 2. gives X = -3, |X| < 1

Kudos [?]: 170 [0], given: 0

Senior Manager
Senior Manager
avatar
Joined: 05 Oct 2005
Posts: 485

Kudos [?]: 6 [0], given: 0

 [#permalink]

Show Tags

New post 07 Dec 2005, 19:36
Bhai, how does statement 1 allow x to be -3 ?

(1) |x + 1| = 2|x - 1|

|-3+1| <> 2|-3-1|
2 <> 8

The final answer is correct, but 1) allows x to be either 1 or 1/3, as duttsit explained.

Am i missing something?

Duttsit, Is there an intuitive way to derive the 2 possible values for x, or must we do it by plugging numbers? (I was able to get 3, but didn't realize 1/3 satisfied the equation too).

Thanks

Kudos [?]: 6 [0], given: 0

  [#permalink] 07 Dec 2005, 19:36
Display posts from previous: Sort by

Is |x|< 1? (1) |x + 1| = 2|x - 1| (2) |x - 3| ? 0

  post reply Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.