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# Is |x| < 1 1) |x+1| = 2 |x-1| 2) |x-3| not equal to 0 If

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Joined: 06 Dec 2005
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Is |x| < 1 1) |x+1| = 2 |x-1| 2) |x-3| not equal to 0 If [#permalink]

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07 Dec 2005, 21:12
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is |x| < 1
1) |x+1| = 2 |x-1|
2) |x-3| not equal to 0

If 2 different representatives are to be selected at random from a group of 10 employees and if p is the probability tha both representatives selected will be women is p> 1/2 ?
1) More than 1/2 of the 10 employees are women
2) The probablility that both representatives selected will be men is less than 1/10

Can someone help me with this. Thanks!!!!!

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Senior Manager
Joined: 05 Oct 2005
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07 Dec 2005, 21:32
The first one can be found here:
http://www.gmatclub.com/phpbb/viewtopic.php?t=23933

Quote:
If 2 different representatives are to be selected at random from a group of 10 employees and if p is the probability tha both representatives selected will be women is p> 1/2 ?
1) More than 1/2 of the 10 employees are women
2) The probablility that both representatives selected will be men is less than 1/10

1) There must be atleast 6 women: 6/10 * 5/9 = 30/90 = 1/3 .... 1/3 < 1/2
If there are 9 women: 9/10 *8/9 = 72/90 .... 72/90 > 1/2
ST 1 is INSUFF

2) There must be at most 3 men. The max number of women is 7: 7/10 * 6/9 = 42/90 .....42/90 < 1/2. Therefore, the answer to the problem is NO. P is always less than 1/2.
ST 2 is SUFF

Ans B.

Is this right?

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Intern
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08 Dec 2005, 21:46

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Senior Manager
Joined: 05 Oct 2005
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08 Dec 2005, 22:24
Can you post the OE please

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08 Dec 2005, 22:24
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