Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Official Answer and Stats are available only to registered users. Register/Login.

_________________

Encourage me by pressing the KUDOS if you find my post to be helpful.

Help me win "The One Thing You Wish You Knew - GMAT Club Contest" http://gmatclub.com/forum/the-one-thing-you-wish-you-knew-gmat-club-contest-140358.html#p1130989

(1) x > 2^34 --> we should compare \(2^{34}\) and \(10^{10}\) --> take the square root from both: we should compare \(2^{17}\) and \(10^5=100,000\). Now, \(2^{17}=2^{10}*2^7=1,024*128>100,000\). Sufficient.

(2) x = 2^35. Since we have the exact numerical value of x we should be able compare it to 10^10 and answer the question. It really doesn't matter whether 2^35>10^10, the main point is that we have sufficient information to get the answer. Sufficient.

Re: Is x > 10^10 ? (1) x > 2^34 (2) x = 2^35 [#permalink]

Show Tags

30 Jul 2012, 02:09

8

This post received KUDOS

dvinoth86 wrote:

Is x > 10^10 ?

(1) x > 2^34 (2) x = 2^35

(1) Let's see if \(2^{34}>10^{10}\).

\(2^{34}>2^{10}*5^{10}\). Divide through by \(2^{10}\), and we get \(2^{24}>5^{10}\). Take the square root of both sides: \(2^{12}>5^5\). This we can compute quite easily, and we find that 1024*4=4096 > 625*5= 3125, TRUE. Sufficient.

(2) We have already seen that (1) is sufficient, obviously (2) is also sufficient. Just to play with powers, we can check that \(2^{35}>10^{10}\): Start again with \(2^{35}>2^{10}*5^{10}\), divide through by \(2^{10}\), then \(2^{25}>5^{10}\). Now we can take the 5th order root of both sides and obtain \(2^5>5^2\) or 32 > 25, TRUE.

Thus, answer D.
_________________

PhD in Applied Mathematics Love GMAT Quant questions and running.

Re: Is x > 10^10 ? (1) x > 2^34 (2) x = 2^35 [#permalink]

Show Tags

30 Jul 2012, 12:22

2

This post received KUDOS

In my personal opinion, I just don't see this question following the style of the GMAT test writers. Unless, whoever wrote this can confirm that they recently saw a similar idea on the exam.

Re: Is x > 10^10 ? (1) x > 2^34 (2) x = 2^35 [#permalink]

Show Tags

30 Jul 2012, 05:19

1

This post received KUDOS

venmic wrote:

Bunuel rocks this is a very nice solution compared to the other ones I ve seen

Bunuel wrote:

Is x > 10^10 ?

(1) x > 2^34 --> we should compare \(2^{34}\) and \(10^{10}\) --> take the square root from both: we should compare \(2^{17}\) and \(10^5=100,000\). Now, \(2^{17}=2^{10}*2^7=1,024*128>100,000\). Sufficient.

(2) x = 2^35. Since we have the exact numerical value of x we should be able compare it to 10^10 and answer the question. It really doesn't matter whether 2^35>10^10, the main point is that we have sufficient information to get the answer. Sufficient.

Answer: D.

Bunuel's logic for testing assumption (2) is excellent. In the present form of the question, one can use that \(2^{35}>2^{34}\), so once (1) turns out sufficient and necessarily provides the info that \(2^{34}>10^{10}\), testing (2) is very easy. Maybe, it would have been somehow more challenging to choose a smaller exponent in statement (2), like 33, with which direct comparison would have been not so straightforward, and a time saving approach would need similar logic to Bunuel's.
_________________

PhD in Applied Mathematics Love GMAT Quant questions and running.

Why would you need to compute anything in this problem?

Statement 1 gives us a minimum value of x. It doesn't matter if 10^10 is smaller or larger, it is sufficient to answer the question. Statement 2 needs no computation either, which Bunuel already pointed out.

We do need to compare 10^10 and 2^34 in (1). Because if 2^34 were less than 10^10, then the statement wouldn't b sufficient. Consider this:

Is x>10?

(1) x>2. If x=5 then the answer is NO but if x=15, then the answer is YES. Not sufficient.

Re: Is x > 10^10 ? (1) x > 2^34 (2) x = 2^35 [#permalink]

Show Tags

08 Jul 2013, 14:25

1

This post received KUDOS

dvinoth86 wrote:

Is x > 10^10 ?

(1) x > 2^34 (2) x = 2^35

hi,

statement 2 is clear we are able to calculate...HENCE SUFFICIENT for statement 1 2^34=2^10*8^8===>(1 10^10=2^10*5^10===>(2

actually we have to compare 2^34..and 10^10 both of them have 2^10 common...so we have to compare actually 8^8 and 5^10...

5^10=(8-3)^8*25=25*(8-3)^8 lets divide 5^10..with 8^8..==>25*((8-3)/8)^8==>clearly we can see that 25 is multiplied to a very small no.(as bracket number is less than 1,and it has been raised to power 8)==>end resul will be less than 1...==>this proves 8^8 is greater than 5^10....hence...2^34>10^10==>sufficient.

both statements are sufficient..hence D
_________________

When you want to succeed as bad as you want to breathe ...then you will be successfull....

GIVE VALUE TO OFFICIAL QUESTIONS...

GMAT RCs VOCABULARY LIST: http://gmatclub.com/forum/vocabulary-list-for-gmat-reading-comprehension-155228.html learn AWA writing techniques while watching video : http://www.gmatprepnow.com/module/gmat-analytical-writing-assessment : http://www.youtube.com/watch?v=APt9ITygGss

Comparing 2^34 with 10^10 Comparing 2^34 with 2^10 * 5^10 [Now we can cancel out common terms 2^10 from both sides] Comparing 2^24 with 5^10 Comparing (2^2)^12 with 5^10 Comparing (4)^12 with (5)^10 Comparing (4^6)^2 with (5^5)^2 [Now we can cancel out common powers 2 from both sides] Comparing (4)^6 with (5)^5 Comparing (4096) with (3125)

Since 4096 > 3125 therefore, 2^34 > 10^10 SUFFICIENT

Statement 2: x = 2^35

Since I know the exact value of x so a comparison can be established hence the statement is sufficient SUFFICIENT

Re: Is x > 10^10 ? (1) x > 2^34 (2) x = 2^35 [#permalink]

Show Tags

21 Feb 2012, 19:36

u r awesome Bunuel
_________________

Encourage me by pressing the KUDOS if you find my post to be helpful.

Help me win "The One Thing You Wish You Knew - GMAT Club Contest" http://gmatclub.com/forum/the-one-thing-you-wish-you-knew-gmat-club-contest-140358.html#p1130989

Re: Is x > 10^10 ? (1) x > 2^34 (2) x = 2^35 [#permalink]

Show Tags

29 Jul 2012, 20:58

Bunuel rocks this is a very nice solution compared to the other ones I ve seen

Bunuel wrote:

Is x > 10^10 ?

(1) x > 2^34 --> we should compare \(2^{34}\) and \(10^{10}\) --> take the square root from both: we should compare \(2^{17}\) and \(10^5=100,000\). Now, \(2^{17}=2^{10}*2^7=1,024*128>100,000\). Sufficient.

(2) x = 2^35. Since we have the exact numerical value of x we should be able compare it to 10^10 and answer the question. It really doesn't matter whether 2^35>10^10, the main point is that we have sufficient information to get the answer. Sufficient.

Re: Is x > 10^10 ? (1) x > 2^34 (2) x = 2^35 [#permalink]

Show Tags

04 Sep 2012, 02:43

Why would you need to compute anything in this problem?

Statement 1 gives us a minimum value of x. It doesn't matter if 10^10 is smaller or larger, it is sufficient to answer the question. Statement 2 needs no computation either, which Bunuel already pointed out.

Re: Is x > 10^10 ? (1) x > 2^34 (2) x = 2^35 [#permalink]

Show Tags

16 Feb 2013, 13:19

Bunuel wrote:

Is x > 10^10 ?

(1) x > 2^34 --> we should compare \(2^{34}\) and \(10^{10}\) --> take the square root from both: we should compare \(2^{17}\) and \(10^5=100,000\). Now, \(2^{17}=2^{10}*2^7=1,024*128>100,000\). Sufficient.

(2) x = 2^35. Since we have the exact numerical value of x we should be able compare it to 10^10 and answer the question. It really doesn't matter whether 2^35>10^10, the main point is that we have sufficient information to get the answer. Sufficient.

Answer: D.

Bunuel,

I solved it a different way- would you mind checking my approach?

I restructured the qstem to is x =,> 2^11 * 5^11?

(1) x > 2^34

- x has 2^11 therefore 2^35 - 2^11 = 2^24 - estimated 2^2 to be 5 and divided 24 by 2 and got 5^12 - x = 2^11 * 5^12 -------- SUFFICIENT

A very coarse method but I would do this problem by log.

F.S.1 gives logx > 34 log2 = 34*0.3 = 10.2(approx). As problem statement is asking about whether x>10^10, it boils down to logx>10. Thus suficient.

F.S.2 anyways gives the value of logx = 35*0.3. Again logx>10. Sufficient.

D.

Not the best method but pretty quick. I don't think it is a 700+ level question.

Good one. Can you please share some source/ tutorial of this method?

No tutorial as such. Just that they gave a power of 10 in this question and also 2^something. So it just struck me. Worked in this question, might not work always!
_________________

Re: Is x > 10^10 ? (1) x > 2^34 (2) x = 2^35 [#permalink]

Show Tags

08 Dec 2014, 00:34

Bunuel wrote:

Is x > 10^10 ?

(1) x > 2^34 --> we should compare \(2^{34}\) and \(10^{10}\) --> take the square root from both: we should compare \(2^{17}\) and \(10^5=100,000\). Now, \(2^{17}=2^{10}*2^7=1,024*128>100,000\). Sufficient.

(2) x = 2^35. Since we have the exact numerical value of x we should be able compare it to 10^10 and answer the question. It really doesn't matter whether 2^35>10^10, the main point is that we have sufficient information to get the answer. Sufficient.

Answer: D.

Oh Bunuel, you are always awesome. For me, your approach is always faster than Manhanttan's. Highly recommend GMAT club for all GMAT learner!!!

Re: Is x > 10^10 ? (1) x > 2^34 (2) x = 2^35 [#permalink]

Show Tags

27 Dec 2015, 06:10

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________

Its been long time coming. I have always been passionate about poetry. It’s my way of expressing my feelings and emotions. And i feel a person can convey...

Written by Scottish historian Niall Ferguson , the book is subtitled “A Financial History of the World”. There is also a long documentary of the same name that the...

Post-MBA I became very intrigued by how senior leaders navigated their career progression. It was also at this time that I realized I learned nothing about this during my...