Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 26 May 2017, 04:03

# TODAY:

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Is x > 3 ?

Author Message
TAGS:

### Hide Tags

Manager
Joined: 09 Feb 2010
Posts: 70
Followers: 0

Kudos [?]: 103 [1] , given: 4

Is x > 3 ? [#permalink]

### Show Tags

02 Sep 2010, 08:13
1
KUDOS
00:00

Difficulty:

45% (medium)

Question Stats:

63% (01:59) correct 38% (00:46) wrong based on 48 sessions

### HideShow timer Statistics

Is x > 3 ?

(1) (x - 3)(x - 2)(x - 1) > 0
(2) x > 1
[Reveal] Spoiler: OA
Manager
Joined: 09 Feb 2010
Posts: 70
Followers: 0

Kudos [?]: 103 [0], given: 4

### Show Tags

02 Sep 2010, 08:14
I though A would be the answer

as x has to be positive and x has to be greater then 1,2 and 3
Intern
Joined: 14 Mar 2010
Posts: 9
Location: Ct,Usa
Followers: 1

Kudos [?]: 0 [0], given: 3

### Show Tags

02 Sep 2010, 08:20
I also think a is the answer..........

if x has to be +ve then it has to be >1,2,3.

whats the source of this Q?and whats the explanation for E
_________________

Lets form the new generation of Business Leaders and take it to the next level.
Its upto us now..........................Lets START our journey

My Fav. Definition of Success -

Constant Flow of Efforts ll l l l l l l l l l l l l l l l l l l l l l l l l l l l l l ll

SUCCESS STRIKES ..........................l..................l............
Consider a KUDOS for me (:-))

Intern
Joined: 24 Mar 2010
Posts: 49
Followers: 0

Kudos [?]: 13 [0], given: 3

### Show Tags

02 Sep 2010, 08:21
1) Consider;
x = 1.5
(-1.5)(-.5)(.5)>0

or

x= 4
(1)(2)(3) > 0

This shows that x can be greater than or less than 3 so, insufficient.

2) x>1, this is clearly insufficient because x could be 1.5, 4, or any other positive number greater than 1. It does not tell us x is greater than 3.

Put them together and x could still be 1.5 or 4 (x can be less than or greater than 3). So, E, we can't tell from the evidence given.

Thanks,

Jared
Intern
Joined: 02 Aug 2010
Posts: 29
Location: Romania
Schools: Harvard, Wharton, Stanford, Stern, Booth, MIT, IMD, INSEAD, IESE
WE 1: 10 years total WE; 2 yrs entrepreneurship, 8 years in telecom, Big 4 and Commercial Banking
WE 2: Currently in a management position with a commercial bank
Followers: 3

Kudos [?]: 7 [0], given: 2

### Show Tags

02 Sep 2010, 08:28
St 1)

There are 4 combinations of factors so that their product is positive.

(x-3) (x-2) (x-1) > 0
- - +
+ - -
- + -
+ + +

As we can see, x can be both greater and lesser than 3. Insufficient.

St 2) x could be 2 or 4. Insufficient.

Together) the statements tell us that (x-1) is positive. Consequently, we can see above that (x-3) can be either positive or negative. Insufficient.

Posted from GMAT ToolKit
Math Expert
Joined: 02 Sep 2009
Posts: 38894
Followers: 7737

Kudos [?]: 106188 [0], given: 11608

### Show Tags

02 Sep 2010, 08:37
Expert's post
1
This post was
BOOKMARKED
Is $$x>3$$?

(1) $$(x-3)(x-2)(x-1)>0$$

The product of 3 numbers is positive if all three are positive (+++) OR two of them are negative and the third one is positive (+--).

Note that: out of 3 numbers $$x-3$$ is the least one and $$x-1$$ is the biggest one.

$$(+)(+)(+)$$ is when even the least one is positive so when $$x-3>0$$ --> $$x>3$$;
$$(+)(-)(-)$$ is when the biggest one is positive ($$x-1>0$$ --> $$x>1$$) and the next one (hence the leas one too) negative ($$x-2<0$$ --> x<2), so when $$1<x<2$$;

So $$(x-3)(x-2)(x-1)>0$$ means that: $$x>3$$ or $$1<x<2$$ --> $$x$$ may or may not be more than 3. Not sufficient.

(2) $$x>1$$. Clearly insufficient.

(1)+(2) Intersection of the ranges from (1) and (2) is the range we had in (1) $$x>3$$ or $$1<x<2$$, so $$x$$ may or may not be more than 3. Not sufficient.

_________________
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 15457
Followers: 649

Kudos [?]: 209 [0], given: 0

Re: Is x > 3 ? [#permalink]

### Show Tags

29 Mar 2017, 05:42
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Re: Is x > 3 ?   [#permalink] 29 Mar 2017, 05:42
Similar topics Replies Last post
Similar
Topics:
6 Ix x>3? 6 29 Mar 2017, 05:41
4 Is x > 3? 3 11 Oct 2015, 07:47
2 Is x>3? 3 29 Mar 2017, 09:08
6 Is x > 3y ? 9 26 Aug 2015, 02:14
11 Is x > x ^3 ? 16 02 Mar 2016, 11:16
Display posts from previous: Sort by