MathRevolution wrote:
Is \(|x^2|<|x^4|\)?
1) \(x<-1\)
2) \(|x|<|x^3|\)
1. Put any value of x<-1 it'll always be |x^2|<|x^4|. Satisfied.
Exception range [-1,1] avoided.
2. So, x can't be zero. Any +ve or -ve value will satisfy |x|<|x^3|
Exception range [-1,1] avoided.
So, |x^2|<|x^4| True. Put any +ve or -ve value to check. It'll satisfy.
D. Independently sufficient.
Lots of good GMAT sums exploit the anomaly of [-1,1] range.
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