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# Is x^2 < x-|y| ? 1) y>x 2) x<0

Author Message
Intern
Joined: 24 Aug 2011
Posts: 6
Is x^2 < x-|y| ? 1) y>x 2) x<0  [#permalink]

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28 Aug 2011, 01:19
1
00:00

Difficulty:

65% (hard)

Question Stats:

41% (01:12) correct 59% (01:13) wrong based on 39 sessions

### HideShow timer Statistics

Is x^2 x
(2) x<0

OPEN DISCUSSION OF THIS QUESTION IS HERE: is-x-2-x-y-153791.html

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Intern
Status: IT industry - Project Manager
Affiliations: Rotary club and Company award
Joined: 12 Jun 2011
Posts: 14
Location: India
Re: Is x^2 < x-|y| ? 1) y>x 2) x<0  [#permalink]

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28 Aug 2011, 06:18
it should be D.
1) Since Y is greater than x, so x-|y| will mean that it is negative. and x^2 is always positive and hence definite answer.
2) Since x< 0 LHS is +ve and RHS is -ve. Definite answer.
Director
Joined: 01 Feb 2011
Posts: 658
Re: Is x^2 < x-|y| ? 1) y>x 2) x<0  [#permalink]

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30 Aug 2011, 18:27
is x^2< x- y? when y>=0

is x^2<x+y? when y<0

1. Sufficient

y>x

when y>=0 , y>x

=>x-y<0 and x^2 is always positive . No

when y<0 , x<y<0

=> x+y<0 and x^2 is always positive . No

2. Sufficient
x<0
=> x-|y|<0 as |y| is always positive

x^2<x-|y|? No

Manager
Joined: 20 Nov 2010
Posts: 142
Re: Is x^2 < x-|y| ? 1) y>x 2) x<0  [#permalink]

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30 Aug 2011, 23:45
St1: y> x => x - |y| is always -ve .
But x^2 >= 0 Hence we have a definitive answer i.e x^2 < x - |y| is false.

St2: x < 0 => x - |y| => -ve - ( +ve) => -ve
But x^2 >=0 Hence we have a definitive answer i.e x^2 < x - |y| is false.

_________________

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
MGMAT 6 650 (51,31) on 31/8/11
MGMAT 1 670 (48,33) on 04/9/11
MGMAT 2 670 (47,34) on 07/9/11
MGMAT 3 680 (47,35) on 18/9/11
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CR notes
http://gmatclub.com/forum/massive-collection-of-verbal-questions-sc-rc-and-cr-106195.html#p832142
http://gmatclub.com/forum/1001-ds-questions-file-106193.html#p832133
http://gmatclub.com/forum/gmat-prep-critical-reasoning-collection-106783.html
http://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html
http://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html?hilit=chineseburned

Math Expert
Joined: 02 Sep 2009
Posts: 52285
Re: Is x^2 < x-|y| ? 1) y>x 2) x<0  [#permalink]

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15 Dec 2017, 23:57
Is x^2 Is $$x^2+|y| x. Since [m]y > x$$, then obviously $$|y| > x$$. Now, since $$|y| > x$$, then $$|y|+x^2=|y|+(nonnegative \ value)$$ will be also greater than $$x$$. Therefore $$x^2+|y|>x$$ and the answer to the question is NO. Sufficient.

(2) x 0[/m]. Thus $$|y|+x^2=(nonnegative \ value)+positive>0>x$$. Thus the answer to the question is NO. Sufficient.

Hope it's clear.

[b]OPEN DISCUSSION OF THIS QUESTION IS HERE: is-x-2-x-y-153791.html

--== Message from the GMAT Club Team ==--

THERE IS LIKELY A BETTER DISCUSSION OF THIS EXACT QUESTION.
This discussion does not meet community quality standards. It has been retired.

If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

_________________
Re: Is x^2 < x-|y| ? 1) y>x 2) x<0 &nbs [#permalink] 15 Dec 2017, 23:57
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