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Is x^2 < x-|y| ? 1) y>x 2) x<0

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Intern
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Joined: 24 Aug 2011
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Is x^2 < x-|y| ? 1) y>x 2) x<0 [#permalink]

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New post 28 Aug 2011, 02:19
1
00:00
A
B
C
D
E

Difficulty:

  65% (hard)

Question Stats:

41% (01:12) correct 59% (01:13) wrong based on 39 sessions

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Is x^2 x
(2) x<0

OPEN DISCUSSION OF THIS QUESTION IS HERE: is-x-2-x-y-153791.html

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Intern
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Re: Is x^2 < x-|y| ? 1) y>x 2) x<0 [#permalink]

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New post 28 Aug 2011, 07:18
it should be D.
1) Since Y is greater than x, so x-|y| will mean that it is negative. and x^2 is always positive and hence definite answer.
2) Since x< 0 LHS is +ve and RHS is -ve. Definite answer.
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Re: Is x^2 < x-|y| ? 1) y>x 2) x<0 [#permalink]

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New post 30 Aug 2011, 19:27
is x^2< x- y? when y>=0

is x^2<x+y? when y<0

1. Sufficient

y>x

when y>=0 , y>x

=>x-y<0 and x^2 is always positive . No

when y<0 , x<y<0

=> x+y<0 and x^2 is always positive . No


2. Sufficient
x<0
=> x-|y|<0 as |y| is always positive

x^2<x-|y|? No

Answer is D.
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Re: Is x^2 < x-|y| ? 1) y>x 2) x<0 [#permalink]

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New post 31 Aug 2011, 00:45
St1: y> x => x - |y| is always -ve .
But x^2 >= 0 Hence we have a definitive answer i.e x^2 < x - |y| is false.

St2: x < 0 => x - |y| => -ve - ( +ve) => -ve
But x^2 >=0 Hence we have a definitive answer i.e x^2 < x - |y| is false.


Hence answer is D.
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http://gmatclub.com/forum/massive-collection-of-verbal-questions-sc-rc-and-cr-106195.html#p832142
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http://gmatclub.com/forum/how-to-get-6-0-awa-my-guide-64327.html
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Re: Is x^2 < x-|y| ? 1) y>x 2) x<0 [#permalink]

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New post 16 Dec 2017, 00:57
Is x^2 Is \(x^2+|y| x. Since [m]y > x\), then obviously \(|y| > x\). Now, since \(|y| > x\), then \(|y|+x^2=|y|+(nonnegative \ value)\) will be also greater than \(x\). Therefore \(x^2+|y|>x\) and the answer to the question is NO. Sufficient.

(2) x 0[/m]. Thus \(|y|+x^2=(nonnegative \ value)+positive>0>x\). Thus the answer to the question is NO. Sufficient.

Answer: D.

Hope it's clear.

[b]OPEN DISCUSSION OF THIS QUESTION IS HERE: is-x-2-x-y-153791.html


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Re: Is x^2 < x-|y| ? 1) y>x 2) x<0   [#permalink] 16 Dec 2017, 00:57
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