MathRevolution wrote:

Is \(x>(-3)^{\frac{1}{3}}\)?

\(1) x>(-2)^{\frac{1}{3}}\)

\(2) x>(-4)^{\frac{1}{3}}\)

(1) \(-2 > -3 \implies (-2)^{\frac{1}{3}} > (-3)^{\frac{1}{3}} \implies x > (-3)^{\frac{1}{3}}\). Sufficient.

(2) Since \((-4)^{\frac{1}{3}} < (-3)^{\frac{1}{3}}\), we could have \(x < (-3)^{\frac{1}{3}}\) or \(x=(-3)^{\frac{1}{3}}\) or \(x > (-3)^{\frac{1}{3}}\). Insufficient.

The answer is A

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