GMAT Question of the Day - Daily to your Mailbox; hard ones only

 It is currently 21 Apr 2019, 03:54

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Is x > 3?

Author Message
TAGS:

### Hide Tags

Math Expert
Joined: 02 Sep 2009
Posts: 54376

### Show Tags

10 Sep 2017, 21:41
00:00

Difficulty:

25% (medium)

Question Stats:

77% (01:43) correct 23% (01:42) wrong based on 53 sessions

### HideShow timer Statistics

Is x > 3?

(1) $$\frac{(x^2y)^3}{(xy^3)^2} = 3$$

(2) $$x^3y^{(–3)} = 1$$

_________________
Senior PS Moderator
Joined: 26 Feb 2016
Posts: 3386
Location: India
GPA: 3.12

### Show Tags

10 Sep 2017, 22:54
(1) $$\frac{(x^2y)^3}{(xy^3)^2} = 3$$
Simplifying,
$$\frac{(x^6*y^3)}{(x^2*y^6)} = 3$$ => $$\frac{x^{(6-2)}}{y^{(6-3)}} = 3$$ => $$\frac{(x^4)}{(y^3)} = 3$$
Because y can take any value, we cannot say anything clearly about the value of x(Insufficient)

(2) $$x^3y^{(–3)} = 1$$
This can also be written as $$\frac{(x^3)}{(y^3)} = 1$$
Because y can take any value, we cannot say anything clearly about the value of x(Insufficient)

On combining the information from both the statements,
If we divide equation in statement 2 from statement 1
$$\frac{{(x^4)}}{{(y^3)}}*\frac{{(y^3)}}{{(x^3)}} = \frac{3}{1}$$
This simplifies to give x = 3.

Therefore, the equation x>3 will always be false(Sufficient)(Option C)
_________________
You've got what it takes, but it will take everything you've got
Is x > 3?   [#permalink] 10 Sep 2017, 22:54
Display posts from previous: Sort by