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Is x + 2y -­ 3z > 0?

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Joined: 07 Jun 2017
Posts: 177

Kudos [?]: 101 [0], given: 59

Location: India
Concentration: Technology, General Management
GMAT 1: 660 Q46 V38
GPA: 3.6
WE: Information Technology (Computer Software)
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Is x + 2y -­ 3z > 0? [#permalink]

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New post 24 Oct 2017, 22:10
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Difficulty:

  55% (hard)

Question Stats:

53% (01:44) correct 47% (01:00) wrong based on 36 sessions

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Is \(x + 2y -­ 3z > 0\) ?

(1) \(4x ­- 3y ­- z > 0\)
(2) \(3x + 2z -­ 5y > 0\)
[Reveal] Spoiler: OA

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Naveen
email: nkmungila@gmail.com
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Re: Is x + 2y -­ 3z > 0? [#permalink]

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New post 25 Oct 2017, 03:36
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Is x + 2y - 3z > 0?

Statement 1:
4x - 3y - z > 0
(x + 2y - 3z) - 5y + 2z > 0
x + 2y - 3z > 5y - 2z
Statement is insufficient.

Statement 2:
3x - 5y + 2z > 0
(x + 2y - 3z) - 7y + 5z > 0
x + 2y - 3 z > 7y - 5z

Combining statements 1 and 2:
4x - 3y - z > 0 and 3x - 5y + 2z > 0
Adding the inequalities because both are greater than 0 (we can't subtract the inequalities because we don't know if the result is greater than 0 or less than 0 as either could be possible)
7x - 8y - z > 0
(x + 2y - 3z) + 6x - 10y + 2z > 0
x + 2y - 3z > 10y - 2z - 6x
Insufficient.

Answer is E.

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Re: Is x + 2y -­ 3z > 0? [#permalink]

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New post 28 Oct 2017, 11:29
c
combining both statements: subtract statement 2 from 1 it gives x+2y-3z<0.. so is the answer.

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Re: Is x + 2y -­ 3z > 0? [#permalink]

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New post 28 Oct 2017, 11:33
reshamdhaga wrote:
c
combining both statements: subtract statement 2 from 1 it gives x+2y-3z<0.. so is the answer.



Hi reshamdhaga

if you subtract i.e multiply the inequality by -1 then the sign of the inequality will change. then you cannot add the two inequalities.

in this case 3x+2z−­5y>0 will become -3x-2z+5y<0

so you cannot add the two inequalities

answer will be E

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Re: Is x + 2y -­ 3z > 0?   [#permalink] 28 Oct 2017, 11:33
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