Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 30 May 2017, 03:53

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Is X^3 an odd integer? (1) 3 square root X is an odd

Author Message
Director
Joined: 03 May 2007
Posts: 875
Schools: University of Chicago, Wharton School
Followers: 6

Kudos [?]: 209 [0], given: 7

Is X^3 an odd integer? (1) 3 square root X is an odd [#permalink]

### Show Tags

21 Aug 2007, 05:38
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is X^3 an odd integer?

(1) 3 square root X is an odd integer.
(2) X is an odd integer.
VP
Joined: 10 Jun 2007
Posts: 1442
Followers: 7

Kudos [?]: 285 [0], given: 0

### Show Tags

21 Aug 2007, 06:12
Fistail wrote:
Is X^3 an odd integer?

(1) 3 square root X is an odd integer.
(2) X is an odd integer.

D.

If x is odd, then x^3 is odd. Only odd*odd=odd
(1) This one you know that sqrt(x) is odd. Only odd values of x will give its sqrt odd. SUFFICIENT

(2) x is odd, then yes. SUFFICIENT.
Intern
Joined: 04 Dec 2004
Posts: 35
Location: bangalore
Followers: 0

Kudos [?]: 4 [0], given: 0

### Show Tags

21 Aug 2007, 06:24
Clearly, either of the statements are sufficient to answer the question..

D
Intern
Joined: 04 Dec 2004
Posts: 35
Location: bangalore
Followers: 0

Kudos [?]: 4 [0], given: 0

### Show Tags

21 Aug 2007, 07:24
Fistail wrote:
do we know x is an integer?

using statement 1:
since 3*sqrt x is an odd integer => sqrt x is odd integer
=> x is odd integer

using statement 2 : x is an odd integer

So, using either of the statements, we can deduce that x is an odd integer.
So, x^3 has to be odd integer.
Current Student
Joined: 28 Dec 2004
Posts: 3361
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 16

Kudos [?]: 297 [0], given: 2

### Show Tags

21 Aug 2007, 08:15
if the cube-root is an odd integer..then X is an odd integer..sufficinet..

statement 2 ..obvious..
Manager
Joined: 03 Sep 2006
Posts: 233
Followers: 1

Kudos [?]: 23 [0], given: 0

### Show Tags

21 Aug 2007, 19:34
Easy D here.

2 Fistail: there is clear statement everywhere, that X should be integer, so it couldn't be any fractions in this question.
21 Aug 2007, 19:34
Display posts from previous: Sort by