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Group the equation as follows: (x^4)(x^3)(y^2)(z^3)

y^2 will always be +ive x^4 will be positive let x and z be positive (satisfying the second statement): so (x^3)(y^3) will be positive and hence the whole thing will be +ive

Now let x and z be -ve (again satisfying the second statement): so (x^3) will be negative and (z^3) will also be negative. The product will be positive.

I am sure I am missing something. Can some one help? I chose B with the below logic: xz > 0 so XZ[3] > 0 So the question really becomes (XZ)[3] X[4] Y[2] From 2, we know that XZ > 0 And X[4] and Y[2] cannot be negative. There by "B" is sufficient?

I am sure I am missing something. Can some one help? I chose B with the below logic: xz > 0 so XZ[3] > 0 So the question really becomes (XZ)[3] X[4] Y[2] From 2, we know that XZ > 0 And X[4] and Y[2] cannot be negative. There by "B" is sufficient?

Statement 2 is sufficient except in case y is 0. If y is 0, x^7*y^2*z^3 will be 0, not positive. If y is not 0, it will be positive. Hence statement 2 alone is not sufficient. Statement 1 tells you that y is not 0 (because yz is less than 0). Hence you need both statements.

(C)
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If there would have been a >= sign, xz>0 should have been sufficient but as it is not, we need the first statement to confirm that Y is not equal to zero.

Re: Is (x^7)(y^2)(z^3) > 0 ? (1) yz < 0 (2) xz > 0
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17 May 2015, 12:22

Guys, is there any difference between (y^2) and (y)^2. We can be sure that (y)^2 is positive but can we also be sure that (y^2) is positive? (forget about y=0 for a moment)

Re: Is (x^7)(y^2)(z^3) > 0 ? (1) yz < 0 (2) xz > 0
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17 May 2015, 20:35

1

octenisept wrote:

Guys, is there any difference between (y^2) and (y)^2. We can be sure that (y)^2 is positive but can we also be sure that (y^2) is positive? (forget about y=0 for a moment)

thank you

(y^2) and (y)^2 are the same. In both cases, y is squared. y could be anything - the whole of it is squared in both cases.

If y = 2a + b, both representations give (2a + b)^2 = 4a^2 + b^2 + 4ab
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Re: Is (x^7)(y^2)(z^3) > 0 ? (1) yz < 0 (2) xz > 0
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06 Aug 2017, 08:35

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