Bunuel wrote:
Is √x an integer?
(1) x/6 is an odd integer.
(2) x^2 is a multiple of 16.
Question basically wants us to find whether x is a perfect square.
(1) x/6 is an odd integer.
So x=6*odd, which means x is multiple of 2 but not of 4.
Thus x is not a perfect square.
Sufficient
(2) x^2 is a multiple of 16.
If x^2=16*9....yes
If x^2=16*3....no
Insufficient
A
However the value of x differs in both the statements.
Statement I says it is multiple of just 2, while statement II says x is a multiple of at least 4.
If x^2=16*9 is no also.
x^2=16*9 -> x=4*3 -> sqrt(12) is not an integer.