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# Is X even? 1. (x+1) * (x-2) is even 2. (x-3) * (x+5) is odd

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CEO
Joined: 21 Jan 2007
Posts: 2734

Kudos [?]: 1043 [0], given: 4

Location: New York City
Is X even? 1. (x+1) * (x-2) is even 2. (x-3) * (x+5) is odd [#permalink]

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12 Nov 2007, 12:49
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Is X even?

1. (x+1) * (x-2) is even
2. (x-3) * (x+5) is odd

Kudos [?]: 1043 [0], given: 4

VP
Joined: 09 Jul 2007
Posts: 1098

Kudos [?]: 141 [0], given: 0

Location: London
Re: number prop - even products [#permalink]

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12 Nov 2007, 13:04
bmwhype2 wrote:
Is X even?

1. (x+1) * (x-2) is even
2. (x-3) * (x+5) is odd

picking numbers

B.

1. (x+1) * (x-2) is even ---> x can be odd and even

2. (x-3) * (x+5) is odd ---> x has to be even only

Kudos [?]: 141 [0], given: 0

CEO
Joined: 21 Jan 2007
Posts: 2734

Kudos [?]: 1043 [0], given: 4

Location: New York City
Re: number prop - even products [#permalink]

### Show Tags

14 Nov 2007, 03:38
Ravshonbek wrote:
bmwhype2 wrote:
Is X even?

1. (x+1) * (x-2) is even
2. (x-3) * (x+5) is odd

picking numbers

B.

1. (x+1) * (x-2) is even ---> x can be odd and even

2. (x-3) * (x+5) is odd ---> x has to be even only

nice. OA is B

i tend to be more comfortable with technical approaches.

Stem: Is X even?

1. shows products of two terms is even

this can only happen under 2 scenarios
a. e*o = e
b. e*e = e

(x+1) * (x-2) = E
under the first scenario:
x+1 must be even. This only occurs if x is odd.
x-2 must be odd. this only occurs if x is odd.
Therefore, X is odd.

under the second scenario:
]x+1 must be even. This only occurs if x is odd.
x-2 must be even. this occurs if X is even.
X is even or odd.

Therefore, A is insuff.

2. Same approach as 1.
SUFF

Therefore B.

Kudos [?]: 1043 [0], given: 4

Re: number prop - even products   [#permalink] 14 Nov 2007, 03:38
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