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# Is x/m(m^2 + n^2 + k^2) = xm + yn + zk? (1) z/k = x/m (2)

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Senior Manager
Joined: 26 Jul 2005
Posts: 313
Location: Los Angeles
Is x/m(m^2 + n^2 + k^2) = xm + yn + zk? (1) z/k = x/m (2) [#permalink]

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27 Oct 2005, 16:35
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Is x/m(m^2 + n^2 + k^2) = xm + yn + zk?

(1) z/k = x/m
(2) x/m = y/n
Manager
Joined: 20 Mar 2005
Posts: 201
Location: Colombia, South America

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27 Oct 2005, 16:49
I think is C

x/m(m^2 + n^2 + z^2) = xm + yn + zk

that is equal to

xm + xn^2/m + xz^2/n = xm + yn + zk

from I: x/m = y/n then xn = ym and from there (xn*n)/m is equal to
ym*n/m equal to yn

so insuff

from ii, do the same stuff as i and you get zk

so insuff

taking both it works so C
Senior Manager
Joined: 26 Jul 2005
Posts: 313
Location: Los Angeles

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28 Oct 2005, 15:54
Right again - OA is C.
Intern
Joined: 14 Sep 2010
Posts: 22
Re: Is x/m(m^2 + n^2 + k^2) = xm + yn + zk? (1) z/k = x/m (2) [#permalink]

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18 Nov 2011, 03:39
Is x/m(m^2 + n^2+ k^2) = xm + yn + zk?

xm^2 + xn^2 + xk^2 = xmm +ynm +zkm?

Is xn^2 + xk^2 = ynm + zkm?

(1) z/k = x/m (xk = mz)

xk^2 = (xk)k = (mzk)

xn^2 + xk^2 = ynm + zkm =

xn^2 = ynm?
xn = my?

(2) x/m = y/n (xn = my)

xn^2 = (xn)n = (my)n

xn^2 + xk^2 = ynm + zkm =

xk^2 = zkm?
xk = mz?

Put (1) and (2) together

xn^2 + xk^2 = ynm + zkm =

(my)n + (mz)k = ynm + zkm

Both statements used = Answer C

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Senior Manager
Joined: 13 May 2011
Posts: 307
WE 1: IT 1 Yr
WE 2: Supply Chain 5 Yrs
Re: Is x/m(m^2 + n^2 + k^2) = xm + yn + zk? (1) z/k = x/m (2) [#permalink]

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18 Nov 2011, 05:19
is xm^2+xn^2+xk^2=xm^2+ynm+zkm
i. e. xn^2+xk^2=ynm+zkm
statement 1: xk=zm
xn^2=ynm Not Sufficient
Statement 2: ym=xn
xk^2=zkm Not Sufficient
Together: xn^2+xk^2=xn^2+xk^2
Sufficient
Re: Is x/m(m^2 + n^2 + k^2) = xm + yn + zk? (1) z/k = x/m (2)   [#permalink] 18 Nov 2011, 05:19
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