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# Is X percent of Y more than Z percent of W?

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Senior Manager
Joined: 21 Oct 2013
Posts: 435
Is X percent of Y more than Z percent of W? [#permalink]

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27 Aug 2014, 06:43
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6
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Difficulty:

75% (hard)

Question Stats:

56% (01:36) correct 44% (01:37) wrong based on 179 sessions

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Is X percent of Y more than Z percent of W?

(1) X percent of Z is one half of Y percent of W.
(2) X=Y and 2·Z=W
Math Expert
Joined: 02 Sep 2009
Posts: 46190
Re: Is X percent of Y more than Z percent of W? [#permalink]

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27 Aug 2014, 07:10
2
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Is X percent of Y more than Z percent of W?

Is x/100*y > z/100*w ? --> is xy > zw ?

(1) X percent of Z is one half of Y percent of W --> x/100*z = 1/2*y/100*w --> 2xz = yw. If x = y = z = 1 and w = 2, then the answer is NO but if x = y = 10, z = 1 and w = 2, then the answer is YES. Not sufficient.

(2) X=Y and 2·Z=W --> multiply these two: 2xz = yw. The same info as above. Not sufficient.

(1)+(2) We have same insufficient statements. Not sufficient.

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Joined: 16 Dec 2017
Posts: 3
Re: Is X percent of Y more than Z percent of W? [#permalink]

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22 Feb 2018, 04:23
I do not agree!
In case we have x/100*y > z/100*w then the question is wether x/y > z/w
First statement is clearly insufficient, but the seond one is not:

(2) X=Y and 2·Z=W that means x/y=1 and Z/W=1/2, so 1 > 1/2, which is true and that is sufficient.

Please correct me, if i am wrong.

Thank you!
Math Expert
Joined: 02 Sep 2009
Posts: 46190
Re: Is X percent of Y more than Z percent of W? [#permalink]

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22 Feb 2018, 05:11
HERmachine wrote:
I do not agree!
In case we have x/100*y > z/100*w then the question is wether x/y > z/w
First statement is clearly insufficient, but the seond one is not:

(2) X=Y and 2·Z=W that means x/y=1 and Z/W=1/2, so 1 > 1/2, which is true and that is sufficient.

Please correct me, if i am wrong.

Thank you!

x/100*y > z/100*w does not translate to x/y > z/w. It translates to xy > zw.
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Joined: 16 Dec 2017
Posts: 3
Re: Is X percent of Y more than Z percent of W? [#permalink]

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22 Feb 2018, 05:36
Bunuel wrote:
HERmachine wrote:
I do not agree!
In case we have x/100*y > z/100*w then the question is wether x/y > z/w
First statement is clearly insufficient, but the seond one is not:

(2) X=Y and 2·Z=W that means x/y=1 and Z/W=1/2, so 1 > 1/2, which is true and that is sufficient.

Please correct me, if i am wrong.

Thank you!

x/100*y > z/100*w does not translate to x/y > z/w. It translates to xy > zw.

Oook, let's do not not tranlate it at all. So we have (1/100)*(x/y) > (1/100)*(z/w), which is eventually 1/100 > 1/200. Same thing actually
Math Expert
Joined: 02 Sep 2009
Posts: 46190
Re: Is X percent of Y more than Z percent of W? [#permalink]

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22 Feb 2018, 05:42
HERmachine wrote:
Bunuel wrote:
HERmachine wrote:
I do not agree!
In case we have x/100*y > z/100*w then the question is wether x/y > z/w
First statement is clearly insufficient, but the seond one is not:

(2) X=Y and 2·Z=W that means x/y=1 and Z/W=1/2, so 1 > 1/2, which is true and that is sufficient.

Please correct me, if i am wrong.

Thank you!

x/100*y > z/100*w does not translate to x/y > z/w. It translates to xy > zw.

Oook, let's do not not tranlate it at all. So we have (1/100)*(x/y) > (1/100)*(z/w), which is eventually 1/100 > 1/200. Same thing actually

You are missing the point.

The question asks whether $$\frac{x}{100}*y > \frac{z}{100}*w$$ NOT whether $$\frac{x}{100*y} > \frac{z}{100*w}$$
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Intern
Joined: 16 Dec 2017
Posts: 3
Re: Is X percent of Y more than Z percent of W? [#permalink]

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22 Feb 2018, 05:44
Ok, now its clear, thank you!
Manager
Joined: 23 Sep 2016
Posts: 231
Re: Is X percent of Y more than Z percent of W? [#permalink]

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23 Feb 2018, 01:18
goodyear2013 wrote:
Is X percent of Y more than Z percent of W?

(1) X percent of Z is one half of Y percent of W.
(2) X=Y and 2·Z=W

IMO E y*x/100>w*z/100
=xy> wz prove
A zx/100 > wy/100
2zx=wy still we can't prove anything
B no information where we can use these values
C combining both tell us about z=1 but this doesn't show any relation between others.
Re: Is X percent of Y more than Z percent of W?   [#permalink] 23 Feb 2018, 01:18
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