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1) \(x-y>0\) -> x>y, but y may be negative, so it could be the case that \(\frac{x}{y}<0\). 2) \(xy>0\) -> both are larger than 0, therefore their division would be larger than 0. Sufficient.

Case 1: Take y=-4 , x=0 While x-y >0 but the x/y =0 So not sufficient

Case 2: Since xy>0 So , x and y should be either both positive or both negative this gives a definite ans to the question , that is , x/y is always positive Hence Sufficient

x/y>0 will be ONLY when both x and y are of same sign otherwise it is NO..

1) x-y>0.. both POSITIVE 3-2>0..... Ans YES y NEGATIVE but x POSITIVE..y=-2, x=2.... Ans NO Insufficient 2) xy>0.. Possible only when both x and y are of same sign.. Always YES Sufficient