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# Is |x-y|= 1? 1. x and y are consecutive integers 2. x is

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Manager
Joined: 05 Feb 2007
Posts: 139

Kudos [?]: 8 [0], given: 7

Is |x-y|= 1? 1. x and y are consecutive integers 2. x is [#permalink]

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15 May 2008, 12:04
00:00

Difficulty:

(N/A)

Question Stats:

100% (00:01) correct 0% (00:00) wrong based on 2 sessions

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Is |x-y|= 1?

1. x and y are consecutive integers

2. x is even and y is odd

Kudos [?]: 8 [0], given: 7

Manager
Joined: 05 Feb 2007
Posts: 139

Kudos [?]: 8 [0], given: 7

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15 May 2008, 12:35
That's what I got....but it's incorrect.

Kudos [?]: 8 [0], given: 7

Senior Manager
Joined: 19 Apr 2008
Posts: 313

Kudos [?]: 99 [0], given: 0

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15 May 2008, 13:22
giantSwan wrote:
That's what I got....but it's incorrect.

I think its A .

take any consecutive integers |x-y| will be 1 , always .

Kudos [?]: 99 [0], given: 0

Manager
Joined: 05 Feb 2007
Posts: 139

Kudos [?]: 8 [0], given: 7

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15 May 2008, 13:26
rpmodi wrote:
giantSwan wrote:
That's what I got....but it's incorrect.

I think its A .

take any consecutive integers |x-y| will be 1 , always .

can you expand on that?

I though |x-y| = 1

is x-y = 1
y-x = 1

2-1 = 1
1-2 = -1

what am I doing wrong?

Kudos [?]: 8 [0], given: 7

Current Student
Joined: 28 Dec 2004
Posts: 3345

Kudos [?]: 322 [0], given: 2

Location: New York City
Schools: Wharton'11 HBS'12

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15 May 2008, 13:29

i dont know why i wrote E

|x-y| just pick number -3 -2, -3+2=-1

3-2=1...

sufficient

Kudos [?]: 322 [0], given: 2

CEO
Joined: 29 Mar 2007
Posts: 2553

Kudos [?]: 528 [0], given: 0

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15 May 2008, 14:23
giantSwan wrote:
Is |x-y|= 1?

1. x and y are consecutive integers

2. x is even and y is odd

This is a pretty straight forward A.

Just test any consecutive integers. Positive or negative, and even with 0.

2: this is obvs. insuff.

Kudos [?]: 528 [0], given: 0

Senior Manager
Joined: 19 Apr 2008
Posts: 313

Kudos [?]: 99 [0], given: 0

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15 May 2008, 14:54
giantSwan wrote:
rpmodi wrote:
giantSwan wrote:
That's what I got....but it's incorrect.

I think its A .

take any consecutive integers |x-y| will be 1 , always .

can you expand on that?

I though |x-y| = 1

is x-y = 1
y-x = 1

2-1 = 1
1-2 = -1

what am I doing wrong?

2-1 = 1
1-2 = -1 ; your final answer is +1 or -1 and if you take mod of that answer will always be +1 ; |-1| =1 ; |1|=1 and so A is sufficient

Kudos [?]: 99 [0], given: 0

Re: DS: consecutive integers   [#permalink] 15 May 2008, 14:54
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