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Is x > y? (1) x = y + 2 (2) x/2 = y -1

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Is x > y? (1) x = y + 2 (2) x/2 = y -1 [#permalink]

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Is x > y?

(1) x = y + 2
(2) x/2 = y -1

This is easy, but I want to know if you have a method to assign values in the case of clue #2. I want to answer this type of questions as fast as I can. Thanks!
[Reveal] Spoiler: OA

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Re: Is x > y? (1) x = y + 2 (2) x/2 = y -1 [#permalink]

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New post 01 Sep 2010, 18:35
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metallicafan wrote:
This is easy, but I want to know if you have a method to assign values in the case of clue #2. I want to answer this type of questions as fast as I can. Thanks!

Is x>y?

(1) x = y + 2
(2) x/2 = y -1


Is \(x>y\)?

(1) \(x=y+2\) --> if you just read what is written you'll get "\(x\) is 2 more than \(y\)", so \(x\) is more than \(y\). Sufficient.

Or you can substitute \(x\) in the question: is \(x>y\)? --> question becomes: is \(y+2>y\)? is \(2>0\)? YES, 2 is more than 0. So the answer to the question is YES. Sufficient.

(2) \(\frac{x}{2}=y-1\) --> \(x=2y-2\) --> substitute \(x\) in the question: is \(x>y\)? --> question becomes: is \(2y-2>y\)? is \(y>2\)? We don't know that, hence this statement is not sufficient.

As for number plugging:
On DS questions when plugging numbers, goal is to prove that the statement is not sufficient. So we should try to get a YES answer with one chosen number(s) and a NO with another.

Try \(x=0\) then \(y=1\) and the answer to the question is NO;
Increase \(x\): try \(x=10\) then \(y=6\) and the answer to the question is YES.

Two different answer, hence not sufficient.

Answer: A.

Hope it helps.
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Kudos [?]: 132789 [1], given: 12372

Retired Moderator
User avatar
Status: 2000 posts! I don't know whether I should feel great or sad about it! LOL
Joined: 04 Oct 2009
Posts: 1628

Kudos [?]: 1120 [0], given: 109

Location: Peru
Schools: Harvard, Stanford, Wharton, MIT & HKS (Government)
WE 1: Economic research
WE 2: Banking
WE 3: Government: Foreign Trade and SMEs
Re: Is x > y? (1) x = y + 2 (2) x/2 = y -1 [#permalink]

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New post 01 Sep 2010, 18:42
Bunuel wrote:
metallicafan wrote:
This is easy, but I want to know if you have a method to assign values in the case of clue #2. I want to answer this type of questions as fast as I can. Thanks!

Is x>y?

(1) x = y + 2
(2) x/2 = y -1


Is \(x>y\)?

(1) \(x=y+2\) --> if you just read what is written you'll get "\(x\) is 2 more than \(y\)", so \(x\) is more than \(y\). Sufficient.

Or you can substitute \(x\) in the question: is \(x>y\)? --> question becomes: is \(y+2>y\)? is \(2>0\)? YES, 2 is more than 0. So the answer to the question is YES. Sufficient.

(2) \(\frac{x}{2}=y-1\) --> \(x=2y-2\) --> substitute \(x\) in the question: is \(x>y\)? --> question becomes: is \(2y-2>y\)? is \(y>2\)? We don't know that, hence this statement is not sufficient.

As for number plugging:
On DS questions when plugging numbers, goal is to prove that the statement is not sufficient. So we should try to get a YES answer with one chosen number(s) and a NO with another.

Try \(x=0\) then \(y=1\) and the answer to the question is NO;
Increase \(x\): try \(x=10\) then \(y=6\) and the answer to the question is YES.

Two different answer, hence not sufficient.

Answer: A.

Hope it helps.


Thanks Bunuel!, you are the real Master!
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"Life’s battle doesn’t always go to stronger or faster men; but sooner or later the man who wins is the one who thinks he can."

My Integrated Reasoning Logbook / Diary: http://gmatclub.com/forum/my-ir-logbook-diary-133264.html

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Re: Is x > y? (1) x = y + 2 (2) x/2 = y -1 [#permalink]

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Re: Is x > y? (1) x = y + 2 (2) x/2 = y -1   [#permalink] 09 Aug 2017, 08:06
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