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Is x < y ? (1) z + 1 < y (2) z > x

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Bunuel
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Is x < y ? (1) z + 1 < y (2) z > x [#permalink] New post   30 Jan 2017, 10:49
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A
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C
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E

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15% (low)

Question Stats:

79% (00:55) correct 21% (01:06) wrong based on 170 sessions
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Is x < y ?

(1) z + 1 < y
(2) z > x
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C
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rohit8865
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Re: Is x < y ? (1) z + 1 < y (2) z > x [#permalink] New post   31 Jan 2017, 07:46
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Bunuel wrote:
Is x < y ?

(1) z + 1 < y
(2) z > x


(1) insuff ..no info on x
(2) insuff ..no info on y

combining
subtract both to get
1<y-x
1+x<y
thus x<y
suff

Ans C
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BrentGMATPrepNow
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Is x < y ? (1) z + 1 < y (2) z > x [#permalink] New post   31 Jan 2017, 13:40
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Bunuel wrote:
Is x < y ?

(1) z + 1 < y
(2) z > x


Target question: Is x < y ?

Statement 1: z + 1 < y
Without any information about x, it's impossible answer the target question with certainty.
So, statement 1 is NOT SUFFICIENT

Statement 2: z > x
Without any information about y, it's impossible answer the target question with certainty.
So, statement 2 is NOT SUFFICIENT

Statements 1 and 2 combined
Statement 1 tells us that z + 1 < y
Statement 2 tells us that x < z
To COMBINE these inequalities, recognize that z < z + 1
So, we can write: x < z < z + 1 < y
If we ignore the part in the middle, we can conclude that x < y
Since we can answer the target question with certainty, the combined statements are SUFFICIENT

Answer: C

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Re: Is x < y ? (1) z + 1 < y (2) z > x [#permalink] New post   22 Sep 2020, 13:05
Top Contributor
Bunuel wrote:
Is x < y ?

(1) z + 1 < y
(2) z > x



1) No Relation with x; Insufficient
2) No relation with y; insufficient

Togather
1) z+1<y
z+1-y<0
z-y<-1 [substracting from both side]
y-z>1 [Changing sign]

2) Says z>x

As y-z> 1 and z>x so surely y>x.

Ans. C
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gmatclubot
Re: Is x < y ? (1) z + 1 < y (2) z > x [#permalink]
22 Sep 2020, 13:05
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Bunuel
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