Is |x| > |y|? : GMAT Data Sufficiency (DS)
Check GMAT Club Decision Tracker for the Latest School Decision Releases https://gmatclub.com/AppTrack

 It is currently 26 Feb 2017, 16:01

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Is |x| > |y|?

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
TAGS:

### Hide Tags

Manager
Joined: 19 Oct 2011
Posts: 132
Location: India
Followers: 3

Kudos [?]: 381 [6] , given: 33

Is |x| > |y|? (1) x^2 > y^2 (2) x > y [#permalink]

### Show Tags

13 May 2012, 04:22
6
KUDOS
1
This post was
BOOKMARKED
00:00

Difficulty:

25% (medium)

Question Stats:

65% (01:35) correct 35% (00:36) wrong based on 400 sessions

### HideShow timer Statistics

Is |x| > |y|?

(1) x^2 > y^2
(2) x > y
[Reveal] Spoiler: OA

_________________

Encourage me by pressing the KUDOS if you find my post to be helpful.

Help me win "The One Thing You Wish You Knew - GMAT Club Contest"
http://gmatclub.com/forum/the-one-thing-you-wish-you-knew-gmat-club-contest-140358.html#p1130989

VP
Status: Top MBA Admissions Consultant
Joined: 24 Jul 2011
Posts: 1134
GMAT 1: 780 Q51 V48
GRE 1: 1540 Q800 V740
Followers: 125

Kudos [?]: 550 [1] , given: 19

Re: Is |x| > |y|? (1) x^2 > y^2 (2) x > y [#permalink]

### Show Tags

13 May 2012, 06:00
1
KUDOS
Statement 1: x^2 > y^2 => |x| > |y|. Sufficient.
Statement 2: x>y. If x>0 and y>0 then x>y implies |x|>|y|. If x<0 and y<0 then x>y implies |x|<|y|. Insufficient.

A it is.
_________________

GyanOne | Top MBA Rankings and MBA Admissions Blog

Top MBA Admissions Consulting | Top MiM Admissions Consulting

Premium MBA Essay Review|Best MBA Interview Preparation|Exclusive GMAT coaching

Get a FREE Detailed MBA Profile Evaluation | Call us now +91 98998 31738

Current Student
Joined: 07 Sep 2011
Posts: 74
GMAT 1: 660 Q41 V40
GMAT 2: 720 Q49 V39
WE: Analyst (Mutual Funds and Brokerage)
Followers: 3

Kudos [?]: 47 [0], given: 13

Re: Is |x| > |y|? (1) x^2 > y^2 (2) x > y [#permalink]

### Show Tags

27 Jun 2012, 10:19
Is |x| > |y|?
(1) x^2 > y^2
(2) x > y

1) This means |x|>|y|. Sufficient.
2) We do not know signs of x and y. If both were positive, then the statement would be true. If both were negative, then the statement would be false. If they had different signs, we would then need to know the vaue of x and y. INSUFFICIENT.

The answer is A.
Intern
Joined: 18 Mar 2012
Posts: 48
GMAT 1: 690 Q V
GPA: 3.7
Followers: 0

Kudos [?]: 199 [0], given: 117

Is |x| > |y|? [#permalink]

### Show Tags

10 Feb 2013, 04:37
Is |x| > |y|?

(1) x^2 > y^2
(2) x > y

Last edited by Bunuel on 10 Feb 2013, 04:41, edited 1 time in total.
Edited the question.
Math Expert
Joined: 02 Sep 2009
Posts: 37131
Followers: 7261

Kudos [?]: 96716 [1] , given: 10777

Re: Is |x| > |y|? [#permalink]

### Show Tags

10 Feb 2013, 04:50
1
KUDOS
Expert's post
2
This post was
BOOKMARKED
Is |x| > |y|?

(1) x^2 > y^2. Since both sides are non-negative, then we can safely take the square root: |x| > |y|. Sufficient.

Or: "is |x| > |y|?" can be rewritten as: is x^2 > y^2? (we can safely square the whole inequality since both sides are non-negative). This statement directly answers the question. Sufficient.

(2) x > y. Clearly insufficient: consider x=1 and y=0 for an YES answer and x=1 and y=-2 for a NO answer. Not sufficient.

_________________
VP
Status: Final Lap Up!!!
Affiliations: NYK Line
Joined: 21 Sep 2012
Posts: 1096
Location: India
GMAT 1: 410 Q35 V11
GMAT 2: 530 Q44 V20
GMAT 3: 630 Q45 V31
GPA: 3.84
WE: Engineering (Transportation)
Followers: 38

Kudos [?]: 532 [0], given: 70

Re: Is IxI > IyI ? [#permalink]

### Show Tags

26 Feb 2013, 02:59
fozzzy wrote:
Is IxI > IyI ?
(1) x^2 > y^2
(2) x > y

Please provide explanations. Thanks!

Hi fozzy

when IxI = IyI that implies x^2 = Y^2
hence clearly statement 1 is sufficient

But for statement 2 substitute -ve values for x and y to satisfy the inequality....for -vel values you will get an answer to the question at hand ....but for +ve value it will be a definite yes......hence statement 2 is insufficient.
Moreover when IxI = I yI ,than either x = -y or y = -x.........

Hope that helps

Consider kudos if my post helps

Archit
Manager
Joined: 03 Mar 2013
Posts: 91
Location: India
Concentration: General Management, Marketing
GPA: 3.49
WE: Web Development (Computer Software)
Followers: 0

Kudos [?]: 8 [0], given: 6

Re: Is |x| > |y|? (1) x^2 > y^2 (2) x > y [#permalink]

### Show Tags

16 May 2013, 08:36
dvinoth86 wrote:
Is |x| > |y|?

(1) x^2 > y^2
(2) x > y

Stmt1: is sufficients as taking root can give us mod

stmt 2: can be flawed as below:
1. -4 , -5 and 4, 5 substitute for answer.
Senior Manager
Joined: 13 May 2013
Posts: 472
Followers: 3

Kudos [?]: 165 [0], given: 134

Re: Is |x| > |y|? [#permalink]

### Show Tags

30 Jun 2013, 09:51
Is |x| > |y|?

Is x>y?
OR
Is x>-y?

We can also square both sides as we know that x, y are >=0

|x| > |y|
is |x|^2 > |y|^2?
Is x^2 > y^2?

(1) x^2 > y^2

This tells us directly that x^2 is greater than y^2
SUFFICIENT

(2) x > y

5>4
|5| > |4|
5 > 4 (Valid)
Or
-3>-8
|-3| > |-8|
3 > 8 (Invalid)
INSUFFICIENT

(A)
Intern
Joined: 13 May 2014
Posts: 40
Concentration: General Management, Strategy
Followers: 1

Kudos [?]: 60 [1] , given: 1

Re: Is |x| > |y|? [#permalink]

### Show Tags

15 May 2014, 12:36
1
KUDOS
To find out the sufficiency for the problem statement,

Option 1:
x^2 > y^2

Quick (and dirty) method : to look for the cases where the option would lead to contradictory or insufficient conclusions to the problem statement

Looking at modulus function, one can verify by checking the inequality scenario in positive and negative domains.
Using values
i) x= 5,y=4
ii) x=-5,y=4
iii) x=-5,y=-4
iv) x= 5,y=-4 ,
all such cases would lead to a definitive conclusion on inequality |x|>|y|

Otherwise also, x^2 > y^2
=> |x|*|x|>|y|*|y|
=> |x| > |y| .. taking sq. root of both sides(which are positive)

SO, 1st option is sufficient

Option 2 :
x > y
Quick (and dirty) method

Using values
i) x = 5, y = -6
ii) x = 5 , y = 4 ,
both give different conclusions on inequality |x|>|y|

SO, 2nd option is insufficient

correct option is
[Reveal] Spoiler:
(B)

Kudos is the best form of appreciation
Intern
Joined: 21 Jan 2014
Posts: 6
Followers: 0

Kudos [?]: 0 [0], given: 5

Re: Is |x| > |y|? [#permalink]

### Show Tags

15 May 2014, 14:45
gmatacequants wrote:
To find out the sufficiency for the problem statement,

Option 1:
x^2 > y^2

Quick (and dirty) method : to look for the cases where the option would lead to contradictory or insufficient conclusions to the problem statement

Looking at modulus function, one can verify by checking the inequality scenario in positive and negative domains.
Using values
i) x= 5,y=4
ii) x=-5,y=4
iii) x=-5,y=-4
iv) x= 5,y=-4 ,
all such cases would lead to a definitive conclusion on inequality |x|>|y|

Otherwise also, x^2 > y^2
=> |x|*|x|>|y|*|y|
=> |x| > |y| .. taking sq. root of both sides(which are positive)

SO, 1st option is sufficient

Option 2 :
x > y
Quick (and dirty) method

Using values
i) x = 5, y = -6
ii) x = 5 , y = 4 ,
both give different conclusions on inequality |x|>|y|

SO, 2nd option is insufficient

correct option is
[Reveal] Spoiler:
(B)

Kudos is the best form of appreciation

why no consideration is given to decimal values of x and y ?
Director
Joined: 25 Apr 2012
Posts: 728
Location: India
GPA: 3.21
WE: Business Development (Other)
Followers: 43

Kudos [?]: 708 [0], given: 723

Re: Is |x| > |y|? [#permalink]

### Show Tags

15 May 2014, 21:53
dhirajx wrote:
Is $$|x|$$ > $$|y|$$?
(1) $$x^2$$ > $$y^2$$
(2) $$x$$ > $$y$$

Sol:

We need to know whether |x|>|y|

St 1 tells us that x^2>y^2 or $$\sqrt{x^2}$$ > $$\sqrt{y^2}$$
Also |x|=$$\sqrt{x^2}$$
So we have |x|>|y| St 1 is clearly sufficient

St 2 says x>y if x=5,y=3 then |x|>|y|
but if x=-3 and y=-5 then |y|>|x|

Ans is A
_________________

“If you can't fly then run, if you can't run then walk, if you can't walk then crawl, but whatever you do you have to keep moving forward.”

GMAT Club Legend
Joined: 09 Sep 2013
Posts: 13976
Followers: 591

Kudos [?]: 167 [0], given: 0

Re: Is |x| > |y|? [#permalink]

### Show Tags

14 Aug 2015, 07:24
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
GMAT Club Legend
Joined: 09 Sep 2013
Posts: 13976
Followers: 591

Kudos [?]: 167 [0], given: 0

Re: Is |x| > |y|? (1) x^2 > y^2 (2) x > y [#permalink]

### Show Tags

20 Sep 2015, 01:50
Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email.
_________________
Re: Is |x| > |y|? (1) x^2 > y^2 (2) x > y   [#permalink] 20 Sep 2015, 01:50
Similar topics Replies Last post
Similar
Topics:
14 Is |x|/x > |y|/y? 6 19 May 2016, 21:35
16 Is |x + y| > |x - y| ? 5 28 Sep 2014, 04:22
18 Is |x + y| > |x - y| ? 6 25 Sep 2013, 13:07
158 Is |x-y|>|x|-|y| 75 17 Nov 2009, 03:52
4 Is |x - y| > |x + y|? 14 02 Aug 2010, 23:16
Display posts from previous: Sort by

# Is |x| > |y|?

 new topic post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.