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# Is x > y^2 ? 1) x > y+5 2) x^2 - y^2 = 0

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Manager
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Is x > y^2 ? 1) x > y+5 2) x^2 - y^2 = 0 [#permalink]

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12 Sep 2008, 05:48
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Is x > y^2 ?

1) x > y+5

2) x^2 - y^2 = 0
SVP
Joined: 07 Nov 2007
Posts: 1805
Location: New York
Followers: 38

Kudos [?]: 934 [0], given: 5

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12 Sep 2008, 22:20
jjhko wrote:
Is x > y^2 ?

1) x > y+5

2) x^2 - y^2 = 0

1)
x=7 y=1

x > y^2 --> 7>1 true

x=-2 y=-10
x>y^2 --> -2>100 false

insuffcient
2)
x=+-y

x=2 y=2
2>4 false
x=1/2 y=1/2
1/2>1/4 true

insufficient

combined.
x > y+5
and x=+-y
so x=-y y is negative and x is positive.
when x=2 y=-2
2>4 false
when x=1/2 y=-1/2
1/2>1/4 true
insufficient

E
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Director
Joined: 23 Sep 2007
Posts: 787
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Kudos [?]: 192 [1] , given: 0

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13 Sep 2008, 00:16
1
KUDOS
jjhko wrote:
Is x > y^2 ?

1) x > y+5

2) x^2 - y^2 = 0

C

from statement 2:

|x| = |y|

from statement 1:
x > y+5

together, x must be positive and y must be negative, and y must be less than -2.5, so absolute value of y must be greater than 2.5, therefore x must be less than y^2
Re: inequality DS   [#permalink] 13 Sep 2008, 00:16
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