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Is x<y?

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Is x<y?  [#permalink]

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New post 02 Oct 2016, 03:44
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A
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Is x<y?
1) x-y<-4
2) -2x>-2y

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Re: Is x<y?  [#permalink]

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New post 03 Oct 2016, 11:09
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MathRevolution wrote:
Is x < y?
1) x - y < -4
2) -2x > -2y


Target question: Is x < y?

Statement 1: x - y < -4
Add y to both sides to get: x < y - 4
IMPORTANT: we know that y - 4 < y
So, we can combine y - 4 < y with x < y - 4 to get: x < y - 4 < y
From this we can conclude that x < y
Since we can answer the target question with certainty, statement 1 is SUFFICIENT

Statement 2: -2x > -2y
Divide both sides of the inequality by -2 to get: x < y [aside: when we divide both sides of an inequality by a negative value, we must switch the direction of the inequality]
Since we can answer the target question with certainty, statement 2 is SUFFICIENT

Answer:

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Re: Is x<y?  [#permalink]

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New post 02 Oct 2016, 04:42
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MathRevolution wrote:
Is x<y?
1) x-y<-4
2) -2x>-2y


Answer D.

Statement 1 says difference of x and y is negative, which implies x<y. Hence, sufficient.

Statement 2 says -2x > -2 y or -x > -y or x<y. Hence, sufficient.
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Re: Is x<y?  [#permalink]

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New post 02 Oct 2016, 05:21
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Re: Is x<y?  [#permalink]

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New post 04 Oct 2016, 07:21
==> In the original condition, there are 2 variables, so C is likely to be the answer. As 1)=2), and in the case of 1), from x-y<-4<0, you get x-y<0, x<y, hence yes. The answer is D.
Answer: D
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Re: Is x<y?   [#permalink] 15 Oct 2018, 07:25
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