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Is x > y? (1) x + y < 0 (2) x + |y| < −1

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akurathi12
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Is x > y? (1) x + y < 0 (2) x + |y| < −1 [#permalink] New post   25 Dec 2018, 23:16
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Is x > y?

(1) x + y < 0

(2) x + |y| < −1
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B
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rahul16singh28
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Re: Is x > y? (1) x + y < 0 (2) x + |y| < −1 [#permalink] New post   25 Dec 2018, 23:24
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akurathi12 wrote:
Is x > y?

(1) x + y < 0

(2) x + |y| < −1


Statement I:

Consider (x,y) = (0,-1) & (-1,0).... Insufficient.

Statement II:

For this statement to be true.. x < y. Hence, Sufficient.
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Re: Is x > y? (1) x + y < 0 (2) x + |y| < −1 [#permalink] New post   26 Dec 2018, 21:58
rahul16singh28 wrote:
akurathi12 wrote:
Is x > y?

(1) x + y < 0

(2) x + |y| < −1


Statement I:

Consider (x,y) = (0,-1) & (-1,0).... Insufficient.

Statement II:

For this statement to be true.. x < y. Hence, Sufficient.


Thank you so much...
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Re: Is x > y? (1) x + y < 0 (2) x + |y| < −1 [#permalink] New post   Updated on: 26 Dec 2018, 23:19
akurathi12 wrote:
Is x > y?

(1) x + y < 0

(2) x + |y| < −1



Stmt1: Addition of two numbers is less than 0,implies atleast one number is negative.It can be x or y,Insuff
Stmt 2:Modulus is never negative.The addition is less than -1,implies x is negative,and x<y.Suff

Ans.B

Originally posted by StudiosTom on 26 Dec 2018, 22:11.
Last edited by StudiosTom on 26 Dec 2018, 23:19, edited 1 time in total.
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Re: Is x > y? (1) x + y < 0 (2) x + |y| < −1 [#permalink] New post   26 Dec 2018, 23:00
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akurathi12 wrote:
Is x > y?

(1) x + y < 0

(2) x + |y| < −1


Question : Is x > y?

Statement 1: x+y < 0
Case 1: x = -2 and y = 1 i.e. x < y
Case 2: x = 1 and y = -2 i.e. x > y

NOT SUFFICIENT

Statement 2: x + |y| < −1

but |y| is always Greater than or equal to zero

i.e. x < -1 and also |x| > |y| because result is -ve i.e. Value of x is predominant in result

i.e. even if y = -2 (negative) then x must be Less than -3 (smaller than y)

hence, x < y

SUFFICIENT

Answer: Option B
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Re: Is x > y? (1) x + y < 0 (2) x + |y| < 1 [#permalink] New post   21 Jan 2023, 08:47
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Re: Is x > y? (1) x + y < 0 (2) x + |y| < 1 [#permalink]
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