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Re: Is |x| > |y| ? (1) x^2 > y^2 (2) x > y [#permalink]
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graduateprofessor wrote:

stmnt 2: x > y if x and y both positive it gives an answer yes.
If x is positive and y negative it gives an answer No.
if x and y both negative it gives an answer No.
insufficient.


That's not quite right. If x is positive and y is negative, it gives the answer 'Maybe', not 'No'. If x = 5, y = -2, then x > y and |x| > |y|. If x = 2 and y = -5, then x > y and |x| < |y|.

That doesn't affect the answer in this case, but it would be important if the question had told us, for example, that xy < 0.
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Re: Is |x| > |y| ? (1) x^2 > y^2 (2) x > y [#permalink]
GMAT TIGER wrote:
since x^2 and y^2 both are +ve, lxl>lyl


This seems to be a rule that can be used repeatedly.
For example:
x^2 = 36
y^2 = 25
since we're only looking at the absolute value, therefore: 6 > 5. So, lxl>lyl.

Thoughts?
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Re: Is |x| > |y| ? (1) x^2 > y^2 (2) x > y [#permalink]
GMAT TIGER wrote:
x-ALI-x wrote:
Is |x| > |y| ?

1) \(x^2 > y^2\)
2) x > y


A.
1: since x^2 and y^2 both are +ve, lxl>lyl is true. suff..
2: when x>y, x could be 1 and y = -10, or x = 10 and y = -1. insuff.


I guess I could be making a really stupid question, but i've never seen the notation +ve. What does it stand for?
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Re: Is |x| > |y| ? (1) x^2 > y^2 (2) x > y [#permalink]
AdrianPeterson wrote:
GMAT TIGER wrote:
x-ALI-x wrote:
Is |x| > |y| ?

1) \(x^2 > y^2\)
2) x > y


A.
1: since x^2 and y^2 both are +ve, lxl>lyl is true. suff..
2: when x>y, x could be 1 and y = -10, or x = 10 and y = -1. insuff.


I guess I could be making a really stupid question, but i've never seen the notation +ve. What does it stand for?


+ve = positive
-ve = negative
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Re: Is |x| > |y| ? (1) x^2 > y^2 (2) x > y [#permalink]
looks like a 500 level ques....IMO a
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Re: Is |x| > |y| ? (1) x^2 > y^2 (2) x > y [#permalink]
x^2 > y^2 . Squaring both sides gives |x| > |y|
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Re: Is |x| > |y| ? (1) x^2 > y^2 (2) x > y [#permalink]
Is |x| > |y| ?

(1) \(x^2 > y^2\)

Absolute value of x > y. Sufficient.

(2) x > y

We can't conclude anything with this statement. For example:

let x = -4 y = -5

\(-4 > -5\)
\(|4| < |5| \)

Answer is A.
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Re: Is |x| > |y| ? (1) x^2 > y^2 (2) x > y [#permalink]
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